The numpy.tile() function constructs a new array by repeating array – ‘arr’, the number of times we want to repeat as per repetitions. The resulted array will have dimensions max(arr.ndim, repetitions) where, repetitions is the length of repetitions. If arr.ndim > repetitions, reps is promoted to arr.ndim by pre-pending 1’s to it. If arr.ndim < repetitions, reps is promoted to arr.ndim by pre-pending new axis. Syntax :
numpy.tile(arr, repetitions)
Parameters :
array : [array_like]Input array. repetitions : No. of repetitions of arr along each axis.
Return :
An array with repetitions of array - arr as per d, number of times we want to repeat arr
Code 1 :
Python
# Python Program illustrating# numpy.tile()import numpy as geek#Working on 1Darr = geek.arange(5)print("arr : \n", arr)repetitions = 2print("Repeating arr 2 times : \n", geek.tile(arr, repetitions))repetitions = 3print("\nRepeating arr 3 times : \n", geek.tile(arr, repetitions))# [0 1 2 ..., 2 3 4] means [0 1 2 3 4 0 1 2 3 4 0 1 2 3 4]# since it was long output, so it uses [ ... ] |
Output :
arr : [0 1 2 3 4] Repeating arr 2 times : [0 1 2 3 4 0 1 2 3 4] Repeating arr 3 times : [0 1 2 ..., 2 3 4]
Code 2 :
Python
# Python Program illustrating# numpy.tile()import numpy as geekarr = geek.arange(3)print("arr : \n", arr)a = 2 b = 2 repetitions = (a, b)print("\nRepeating arr : \n", geek.tile(arr, repetitions))print("arr Shape : \n", geek.tile(arr, repetitions).shape)a = 3 b = 2 repetitions = (a, b)print("\nRepeating arr : \n", geek.tile(arr, repetitions))print("arr Shape : \n", geek.tile(arr, repetitions).shape)a = 2b = 3 repetitions = (a, b)print("\nRepeating arr : \n", geek.tile(arr, repetitions))print("arr Shape : \n", geek.tile(arr, repetitions).shape) |
Output :
arr : [0 1 2] Repeating arr : [[0 1 2 0 1 2] [0 1 2 0 1 2]] arr Shape : (2, 6) Repeating arr : [[0 1 2 0 1 2] [0 1 2 0 1 2] [0 1 2 0 1 2]] arr Shape : (3, 6) Repeating arr : [[0 1 2 ..., 0 1 2] [0 1 2 ..., 0 1 2]] arr Shape : (2, 9)
Code 3 : (repetitions == arr.ndim) == 0
Python
# Python Program illustrating# numpy.tile()import numpy as geekarr = geek.arange(4).reshape(2, 2)print("arr : \n", arr)a = 2 b = 1 repetitions = (a, b)print("\nRepeating arr : \n", geek.tile(arr, repetitions))print("arr Shape : \n", geek.tile(arr, repetitions).shape)a = 3 b = 2 repetitions = (a, b)print("\nRepeating arr : \n", geek.tile(arr, repetitions))print("arr Shape : \n", geek.tile(arr, repetitions).shape)a = 2b = 3 repetitions = (a, b)print("\nRepeating arr : \n", geek.tile(arr, repetitions))print("arr Shape : \n", geek.tile(arr, repetitions).shape) |
Output :
arr : [[0 1] [2 3]] Repeating arr : [[0 1] [2 3] [0 1] [2 3]] arr Shape : (4, 2) Repeating arr : [[0 1 0 1] [2 3 2 3] [0 1 0 1] [2 3 2 3] [0 1 0 1] [2 3 2 3]] arr Shape : (6, 4) Repeating arr : [[0 1 0 1 0 1] [2 3 2 3 2 3] [0 1 0 1 0 1] [2 3 2 3 2 3]] arr Shape : (4, 6)
References : https://docs.scipy.org/doc/numpy/reference/generated/numpy.tile.html Note : These codes won’t run on online IDE’s. Please run them on your systems to explore the working . This article is contributed by Mohit Gupta_OMG 😀. If you like Lazyroar and would like to contribute, you can also write an article using write.neveropen.co.za or mail your article to review-team@neveropen.co.za. See your article appearing on the Lazyroar main page and help other Geeks. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
