numpy.outer() function compute the outer product of two vectors.
Syntax : numpy.outer(a, b, out = None)
Parameters :
a : [array_like] First input vector. Input is flattened if not already 1-dimensional.
b : [array_like] Second input vector. Input is flattened if not already 1-dimensional.
out : [ndarray, optional] A location where the result is stored.Return : [ndarray] Returns the outer product of two vectors. out[i, j] = a[i] * b[j]
Code #1 :
# Python program explaining # numpy.outer() function # importing numpy as geek import numpy as geek a = geek.ones(4) b = geek.linspace(-1, 2, 4) gfg = geek.outer(a, b) print (gfg) |
Output :
[[-1. 0. 1. 2.] [-1. 0. 1. 2.] [-1. 0. 1. 2.] [-1. 0. 1. 2.]]
Code #2 :
# Python program explaining # numpy.outer() function # importing numpy as geek import numpy as geek a = geek.ones(5) b = geek.linspace(-2, 2, 5) gfg = geek.outer(a, b) print (gfg) |
Output :
[[-2. -1. 0. 1. 2.] [-2. -1. 0. 1. 2.] [-2. -1. 0. 1. 2.] [-2. -1. 0. 1. 2.] [-2. -1. 0. 1. 2.]]
