numpy.ma.ediff1d() function return the differences between consecutive elements of an array.
Syntax : numpy.ma.ediff1d(arr, to_end = None, to_begin = None)
Parameters :
arr : [array_like] Input array.
to_end : [array_like, optional] Number to append at the end of the returned differences.
to_begin : [array_like, optional] Number to prepend at the beginning of the returned differences.Return : Return the differences between consecutive elements of an array.
Code #1:
Python3
# Python program explaining # numpy.ma.ediff1d() function # importing numpy as geek import numpy as geek arr = geek.array([3, 5, 8, 4, 12]) gfg = geek.ma.ediff1d(arr) print(gfg) |
Output:
[ 2 3 -4 8]
Code #2:
Python3
# Python program explaining # numpy.ma.ediff1d() function # importing numpy as geek import numpy as geek arr = geek.array([3, 5, 8, 4, 12]) gfg = geek.ma.ediff1d(arr, to_begin=geek.array([-23, 0]), to_end=25) print(gfg) |
Output:
[-23 0 2 3 -4 8 25]
