Given an array of integers. The task is to find the minimum number of consecutive sequences that can be formed using the elements of the array.
Examples:
Input: arr[] = { -3, -2, -1, 0, 2 }
Output: 2
Consecutive sequences are (-3, -2, -1, 0), (2).
Input: arr[] = { 3, 4, 0, 2, 6, 5, 10 }
Output: 3
Consecutive sequences are (0), {2, 3, 4, 5, 6} and {10}
Approach:
- Sort the array.
- Iterate the array, and check if current element is just 1 smaller than the next element.
- If it is then increment the count by 1.
- Return the final count of consecutive sequences.
Below is the implementation of above approach :
C++
// C++ program find the minimum number of consecutive // sequences in an array#include <bits/stdc++.h>using namespace std;int countSequences(int arr[], int n){ int count = 1; sort(arr, arr + n); for (int i = 0; i < n - 1; i++) if (arr[i] + 1 != arr[i + 1]) count++; return count;}// Driver programint main(){ int arr[] = { 1, 7, 3, 5, 10 }; int n = sizeof(arr) / sizeof(arr[0]); // function call to print required answer cout << countSequences(arr, n); return 0;} |
Java
// Java program find the minimum number of consecutive // sequences in an arrayimport java.util.Arrays; import java.io.*;class GFG { static int countSequences(int arr[], int n){ int count = 1; Arrays.sort(arr); for (int i = 0; i < n - 1; i++) if (arr[i] + 1 != arr[i + 1]) count++; return count;}// Driver program public static void main (String[] args) { int arr[] = { 1, 7, 3, 5, 10 }; int n = arr.length; // function call to print required answer System.out.println( countSequences(arr, n)); }//This code is contributed by ajit. } |
Python3
# Python3 program find the minimum number of consecutive # sequences in an array def countSequences(arr, n) : count = 1 arr.sort() for i in range( n -1) : if (arr[i] + 1 != arr[i + 1]) : count += 1 return count # Driver program if __name__ == "__main__" : arr = [ 1, 7, 3, 5, 10 ] n = len(arr) # function call to print required answer print(countSequences(arr, n)) # This code is contributed by Ryuga |
C#
// C# program find the minimum number of consecutive // sequences in an array using System;class GFG { static int countSequences(int []arr, int n){ int count = 1; Array.Sort(arr); for (int i = 0; i < n - 1; i++) if (arr[i] + 1 != arr[i + 1]) count++; return count;} // Driver program static public void Main (String []args) { int []arr = { 1, 7, 3, 5, 10 }; int n = arr.Length; // function call to print required answer Console.WriteLine( countSequences(arr, n)); }}//This code is contributed by Arnab Kundu |
PHP
<?php// PHP program find the minimum number // of consecutive sequences in an arrayfunction countSequences($arr, $n){ $count = 1; sort($arr); for ($i = 0; $i < $n - 1; $i++) if ($arr[$i] + 1 != $arr[$i + 1]) $count++; return $count;}// Driver Code$arr = array( 1, 7, 3, 5, 10 );$n = count($arr);// function call to print required answerecho countSequences($arr, $n);// This code is contributed by inder_verma?> |
Javascript
<script> // Javascript program find the // minimum number of consecutive // sequences in an array function countSequences(arr, n) { let count = 1; arr.sort(function(a, b){return a - b}); for (let i = 0; i < n - 1; i++) if (arr[i] + 1 != arr[i + 1]) count++; return count; } let arr = [ 1, 7, 3, 5, 10 ]; let n = arr.length; // function call to print required answer document.write(countSequences(arr, n)); </script> |
Output:
5
Time Complexity: O(n log n), where n is the size of the array.
Auxiliary Space: O(1)
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