Given an Array of size N and a values K, around which we need to right rotate the array. How to quickly print the right rotated array?
Examples :
Input: Array[] = {1, 3, 5, 7, 9}, K = 2. Output: 7 9 1 3 5 Explanation: After 1st rotation - {9, 1, 3, 5, 7} After 2nd rotation - {7, 9, 1, 3, 5} Input: Array[] = {1, 2, 3, 4, 5}, K = 4. Output: 2 3 4 5 1
Approach:
- We will first take mod of K by N (K = K % N) because after every N rotations array will become the same as the initial array.
- Now, we will iterate the array from i = 0 to i = N-1 and check,
- If i < K, Print rightmost Kth element (a[N + i -K]). Otherwise,
- Print array after ‘K’ elements (a[i – K]).
- If i < K, Print rightmost Kth element (a[N + i -K]). Otherwise,
Below is the implementation of the above approach.
Javascript
// Javascript implementation of right rotation // of an array K number of times // Function to rightRotate array function RightRotate(a, n, k) { // If rotation is greater // than size of array k = k % n; for (let i = 0; i < n; i++) { if (i < k) { // Printing rightmost // kth elements document.write(a[n + i - k] + " " ); } else { // Prints array after // 'k' elements document.write((a[i - k]) + " " ); } } document.write( "<br>" ); } // Driver code let Array = [1, 2, 3, 4, 5]; let N = Array.length; let K = 2; RightRotate(Array, N, K); // This code is contributed by gfgking. |
Output:
4 5 1 2 3
Time complexity : O(n)
Auxiliary Space : O(1)
Please refer complete article on Print array after it is right rotated K times for more details!
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