Given a matrix of order m*n then the task is to find the frequency of even and odd numbers in matrix
Examples:
Input : m = 3, n = 3
{ 1, 2, 3 },
{ 4, 5, 6 },
{ 7, 8, 9 }
Output : Frequency of odd number = 5
Frequency of even number = 4
Input : m = 3, n = 3
{ 10, 11, 12 },
{ 13, 14, 15 },
{ 16, 17, 18 }
Output : Frequency of odd number = 4
Frequency of even number = 5
Javascript
<script>// Java Script Program to Find the frequency// of even and odd numbers in a matrixlet MAX = 100;// function for calculating frequencyfunction freq(ar,m,n) { let even = 0, odd = 0; for (let i = 0; i < m; ++i) { for (let j = 0; j < n; ++j) { // even and odd if ((ar[i][j] % 2) == 0) ++even; else ++odd; } } // print Frequency of numbers document.write(" Frequency of odd number =" + odd + " <br>"); document.write(" Frequency of even number = " + even + "<br>");}// Driver code let m = 3, n = 3; let array = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]; freq(array, m, n);// This code is contributed by sravan kumar G</script> |
Output:
Frequency of odd number = 5 Frequency of even number = 4
Time Complexity: O(m*n)
Auxiliary Space: O(1)
Method: Using bitwise & operator
Javascript
<script>// Java Script Program to Find the frequency// of even and odd numbers in a matrixlet MAX = 100;// function for calculating frequencyfunction freq(ar,m,n) { let even = 0, odd = 0; for (let i = 0; i < m; ++i) { for (let j = 0; j < n; ++j) { // even and odd //checking using bitwise & operator if ((ar[i][j]&1) == 0) ++even; else ++odd; } } // print Frequency of numbers document.write(" Frequency of odd number =" + odd + " <br>"); document.write(" Frequency of even number = " + even + "<br>");}// Driver code let m = 3, n = 3; let array = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]; freq(array, m, n);// This code is contributed by tvsk</script> |
Output:
Frequency of odd number = 5 Frequency of even number = 4
Time Complexity: O(m*n)
Auxiliary Space: O(1)
Please refer complete article on Frequencies of even and odd numbers in a matrix for more details!
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