A square is a simple flat shape in a plane, defined by four points at the four corners. It has four sides with equal length and four corners with right angles.
Method Overloading: Method overloading allows different methods to have the same name, but different signatures where the signature can differ by the number of input parameters or type of input parameters, or both.
In this article, we will learn how to find the area of the square using the method overloading.
Area of the Square
The area of the square is the square of its sides. We can simply calculate the area of the square using the following formula:
Formula:
Area of the Square: A = a2
Here, a is the side of the square.
Below is the implementation of the above approach:
Example 1:
Showing the method overloading of Area() function which has different parameters of square sides of different data-type( float , int , double)
Java
// Java program to find the area of// the square using Method Overloading// of parameters with different datatype// of sidesimport java.io.*;class Square { // Overloaded Area() function to // calculate the area of the square // It takes one double parameter void Area(double side) { System.out.println("Area of the Square: " + side * side); } // Overloaded Area() function to // calculate the area of the square // It takes one float parameter void Area(float side) { System.out.println("Area of the Square: " + side * side); }}class GFG { // Driver code public static void main(String[] args) { // Creating object of square class Square obj = new Square(); // Calling function obj.Area(10); obj.Area(3.2); }} |
Area of the Square: 100.0 Area of the Square: 10.240000000000002
Example 2:
Showing method overloading of Area() function which returns the area of different figures like( square, circle, rectangle)
Java
// Java program to find the area of// the multiple shapes// using Method Overloadingimport java.io.*;class Shape { static final double PI = Math.PI; // Overloaded Area() function to // calculate the area of the square // It takes one float parameter void Area(float a) { float A = a * a; System.out.println("Area of the Square: " + A); } // Overloaded Area() function to // calculate the area of the circle // It takes one double parameter void Area(double a) { double A = PI * a * a; System.out.println("Area of the Circle: " + A); } // Overloaded Area() function to // calculate the area of the rectangle // It takes two int parameters void Area(int a, int b) { int A = a * b; System.out.println("Area of the Rectangle: " + A); }}class GFG { // Driver code public static void main(String[] args) { // Creating object of Shape class Shape obj = new Shape(); // Calling function obj.Area(10.5); obj.Area(3); obj.Area(5, 4); }} |
Area of the Circle: 346.36059005827474 Area of the Square: 9.0 Area of the Rectangle: 20
Time complexity: O(1) because it is doing constant operations
Auxiliary space: O(1)
