Given a String count the total number of vowels and consonants in this given string. Assuming String may contain only special characters, or white spaces, or a combination of all. The idea is to iterate the string and checks if that character is present in the reference string or not. If a character is present in the reference increment number of vowels by 1, otherwise, increment the number of consonants by 1.
Example:
Input : String = "Lazyroar"
Output: Number of Vowels = 5
Number of Consonants = 8
Input : String = "Alice"
Output: Number of Vowels = 3
Number of Consonants = 2
Approach:
- Create two variables vow and cons and initialize them with 0.
- Start string traversing.
- If i’th character is vowel then increment in vow variable by 1.
- Else if the character is consonant then increment in cons variable by 1.
Example
Java
// Java Program to Count Total Number of Vowels// and Consonants in a String// Importing all utility classesimport java.util.*;// Main classclass GFG { // Method 1 // To prints number of vowels and consonants public static void count(String str) { // Initially initializing elements with zero // as till now we have not traversed int vow = 0, con = 0; // Declaring a reference String // which contains all the vowels String ref = "aeiouAEIOU"; for (int i = 0; i < str.length(); i++) { // Check for any special characters present // in the given string if ((str.charAt(i) >= 'A' && str.charAt(i) <= 'Z') || (str.charAt(i) >= 'a' && str.charAt(i) <= 'z')) { if (ref.indexOf(str.charAt(i)) != -1) vow++; else con++; } } // Print and display number of vowels and consonants // on console System.out.println("Number of Vowels = " + vow + "\nNumber of Consonants = " + con); } // Method 2 // Main driver method public static void main(String[] args) { // Custom string as input String str = "#Lazyroar"; // Calling the method 1 count(str); }} |
Output
Number of Vowels = 5 Number of Consonants = 8
Time Complexity: O(n²) here, n is the length of the string.
