Boolean values are true/false. In this program, we need to check if any two out of three boolean values are true or not.
We will be discussing two major approaches to do it:
Approach 1: Using if-else condition
We initialize three boolean variable flags, with either a boolean FALSE or a TRUE value.
The counter approach can be used to check if two out of these three boolean variables are TRUE, by incrementing the counter value for each TRUE value.
Java
// Java program to check if// two out of three boolean// variables are true import java.io.*; class GFG { public static void main(String[] args) { boolean flag1 = true; boolean flag2 = true; boolean flag3 = false; // maintaining a counter int cnt = 0; // check if flag1 is true, increment counter if (flag1) cnt += 1; // check if flag2 is true, increment counter if (flag2) cnt += 1; // check if flag3 is true, increment counter if (flag3) cnt += 1; // check counter value if (cnt == 2) System.out.println("Two flags are true!"); else System.out.println("Two flags are not true!"); }} |
Output
Two flags are true!
- Time Complexity: O(1)
- Space Complexity: O(1)
Another Method: Here, we will check if flag1 is true, then the ans should be true if either of flag2 or flag3 is true. Otherwise, if flag1 is false, then ans will be true when both flag2 and flag3 are true.
Java
// Java program to check // if two out of three boolean// variables are true import java.io.*; class GFG { public static void main(String[] args) { boolean flag1 = true; boolean flag2 = true; boolean flag3 = false; // to store the result boolean ans = false; if (flag1) { ans = flag2 || flag3; } else { ans = flag2 && flag3; } if (ans) System.out.println("Two flags are true!"); else System.out.println("Two flags are not true!"); }} |
Output
Two flags are true!
- Time Complexity: O(1)
- Space Complexity: O(1)
Approach 3: Using the ternary operator
Java
// Java program to check if// two out of three boolean// variables are trueimport java.io.*; class GFG { public static void main(String[] args) { boolean flag1 = true; boolean flag2 = true; boolean flag3 = true; // to store the result boolean ans = false; ans = flag1 ? flag2 || flag3 : flag2 && flag3; if (ans) System.out.println("Two flags are true!"); else System.out.println("Two flags are not true!"); }} |
Output
Two flags are not true!
- Time Complexity: O(1)
- Space Complexity: O(1)
