The Stooge sort is a recursive sorting algorithm. It is defined as below (for ascending order sorting).
Step 1 : If value at index 0 is greater than value at last index, swap them. Step 2: Recursively, a) Stooge sort the initial 2/3rd of the array. b) Stooge sort the last 2/3rd of the array. c) Stooge sort the initial 2/3rd again to confirm.
Java
// Java program to implement stooge sort import java.io.*; Â
public class stooge {  // Function to implement stooge sort  static void stoogesort( int arr[], int l, int h)  {   if (l >= h)   return ; Â
  // If first element is smaller   // than last,swap them   if (arr[l] > arr[h])   {    int t = arr[l];    arr[l] = arr[h];    arr[h] = t;   } Â
  // If there are more than 2 elements in   // the array   if (h-l+ 1 > 2 )   {    int t = (h-l+ 1 ) / 3 ; Â
   // Recursively sort first 2/3 elements    stoogesort(arr, l, h-t); Â
   // Recursively sort last 2/3 elements    stoogesort(arr, l+t, h); Â
   // Recursively sort first 2/3 elements    // again to confirm    stoogesort(arr, l, h-t);   }  } Â
 // Driver Code  public static void main(String args[])  {   int arr[] = { 2 , 4 , 5 , 3 , 1 };   int n = arr.length; Â
  stoogesort(arr, 0 , n- 1 ); Â
  for ( int i= 0 ; i < n; i++)    System.out.print(arr[i] + " " );  } } // Code Contributed by Mohit Gupta_OMG <(0_o)> |
Output:
1 2 3 4 5
Time Complexity:
The running time complexity of stooge sort can be written as,
T(n) = 3T(3n/2) + O(1)
Solution of above recurrence is O(n(log3/log1.5)) = O(n2.709), hence it is slower than even bubble sort(n2).
Auxiliary Space: O(n)
Please refer complete article on Stooge Sort for more details!
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!