The method pow(int b, int k) of Guava’s IntMath class returns b to the kth power. Even if the result overflows, it will be equal to BigInteger.valueOf(b).pow(k).intValue(). This implementation runs in O(log k) time.
Syntax:
public static int pow(int b, int k)
Exception: The method pow(int b, int k) throws IllegalArgumentException if k < 0.
Example 1:
// Java code to show implementation of// pow(int b, int k) method of Guava's// IntMath class import java.math.RoundingMode;import com.google.common.math.IntMath; class GFG { static int findPow(int b, int k) { // Using pow(int b, int k) // method of Guava's IntMath class int ans = IntMath.pow(b, k); // Return the answer return ans; } // Driver code public static void main(String args[]) { int b = 4; int k = 5; int ans = findPow(b, k); System.out.println(b + " to the " + k + "th power is: " + ans); b = 12; k = 3; ans = findPow(b, k); System.out.println(b + " to the " + k + "th power is: " + ans); }} |
Output:
4 to the 5th power is: 1024 12 to the 3th power is: 1728
Example 2 :
// Java code to show implementation of// pow(int b, int k) method of Guava's// IntMath classimport java.math.RoundingMode;import com.google.common.math.IntMath; class GFG { static int findPow(int b, int k) { try { // Using pow(int b, int k) // method of Guava's IntMath class // This should throw "IllegalArgumentException" // as k < 0 int ans = IntMath.pow(b, k); // Return the answer return ans; } catch (Exception e) { System.out.println(e); return -1; } } // Driver code public static void main(String args[]) { int b = 4; int k = -5; try { // Using pow(int b, int k) // method of Guava's IntMath class // This should throw "IllegalArgumentException" // as k < 0 IntMath.pow(b, k); } catch (Exception e) { System.out.println(e); } }} |
Output:
java.lang.IllegalArgumentException: exponent (-5) must be >= 0
