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Infinite Loop Puzzles in Java

Problem 1 : Insert code in the given code segments to make the loop infinite.




class GFG
{
public static void main(String s[]){

/* Insert code here */

for (int i = start; i <= start + 1; i++) {
/* Infinite loop */
}
}
}


Solution:
It looks as though it should run for only two iterations, but it can be made to loop indefinitely by taking advantage of the overflow behavior.
Integer.MAX_VALUE is the maximum value that an int can store in Java. When i gets to Integer.MAX_VALUE and is incremented, it silently wraps around to Integer.MIN_VALUE. So, we can declare variable start with 1 less than maximum value.
Following is the solution:




class GFG
{
public static void main(String s[]){

int start = Integer.MAX_VALUE-1;
for (int i = start; i <= start + 1; i++) {
/* Infinite loop */
}
}
}


In this, start=2147483645 (Integer.MAX_VALUE-1), and the value goes like 2147483645, 2147483646, -2147483648, -2147483647…….. and so on.

 

Problem 2 Insert code in the given code segments to make the loop infinite.




class GFG
{
public static void main(String s[]) {

/* Insert code here */

while (i <= j && j <= i && i != j) {
/* Infinite loop */
}
}
}


Solution:
Until release 5.0, Java’s numerical comparison operators (=) required both of their operands to be of a primitive numeric type (byte, char, short, int, long, float, or double). In release 5.0, the specification was changed to say that the type of each operand must be convertible to a primitive numeric type. Therein lies the rub.
In release 5.0, autoboxing and auto-unboxing were added to the language. We are using this in the following :




class GFG
{
public static void main(String s[]){
Integer i = new Integer(0);
Integer j = new Integer(0);
while (i <= j && j <= i && i != j) {
/* Infinite loop */
}
}
}


The first two subexpressions (i <= j and j <= i) perform unboxing conversions on i and j and compare the resulting int values numerically. Both i and j represent 0, so both of these subexpressions evaluate to true. The third subexpression (i != j) performs an identity comparison on the object references i and j. The two variables refer to distinct objects, as each was initialized to a new Integer instance. Therefore, the third subexpression also evaluates to true, and the loop spins forever.

This article is contributed by Shubham Juneja. If you like Lazyroar and would like to contribute, you can also write an article using contribute.neveropen.co.za or mail your article to contribute@neveropen.co.za. See your article appearing on the Lazyroar main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

Nokonwaba Nkukhwana
Experience as a skilled Java developer and proven expertise in using tools and technical developments to drive improvements throughout a entire software development life cycle. I have extensive industry and full life cycle experience in a java based environment, along with exceptional analytical, design and problem solving capabilities combined with excellent communication skills and ability to work alongside teams to define and refine new functionality. Currently working in springboot projects(microservices). Considering the fact that change is good, I am always keen to new challenges and growth to sharpen my skills.
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