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How to split a string in C/C++, Python and Java?

Splitting a string by some delimiter is a very common task. For example, we have a comma-separated list of items from a file and we want individual items in an array. 
Almost all programming languages, provide a function split a string by some delimiter. 

In C:  

// Splits str[] according to given delimiters.
// and returns next token. It needs to be called
// in a loop to get all tokens. It returns NULL
// when there are no more tokens.
char * strtok(char str[], const char *delims);

C




// A C/C++ program for splitting a string
// using strtok()
#include <stdio.h>
#include <string.h>
 
int main()
{
    char str[] = "Geeks-for-Geeks";
 
    // Returns first token
    char *token = strtok(str, "-");
   
    // Keep printing tokens while one of the
    // delimiters present in str[].
    while (token != NULL)
    {
        printf("%s\n", token);
        token = strtok(NULL, "-");
    }
 
    return 0;
}


Output: Geeks
    for
    Geeks

Time complexity : O(n)

Auxiliary Space: O(n)

In C++

Note:  The main disadvantage of strtok() is that it only works for C style strings.
       Therefore we need to explicitly convert C++ string into a char array.
       Many programmers are unaware that C++ has two additional APIs which are more elegant
       and works with C++ string. 

Method 1: Using  stringstream API of C++

Prerequisite:  stringstream API 

Stringstream object can be initialized using a string object, it automatically tokenizes strings on space char. Just like “cin” stream stringstream allows you to read a string as a stream of words. Alternately, we can also utilise getline function to tokenize string on any single character delimiter.

Some of the Most Common used functions of StringStream.
clear() — flushes the stream 
str() —  converts a stream of words into a C++ string object.
operator << — pushes a string object into the stream.
operator >> — extracts a word from the stream.

 The code below demonstrates it. 

C++




#include <bits/stdc++.h>
using namespace std;
 
// A quick way to split strings separated via spaces.
void simple_tokenizer(string s)
{
    stringstream ss(s);
    string word;
    while (ss >> word) {
        cout << word << endl;
    }
}
 
// A quick way to split strings separated via any character
// delimiter.
void adv_tokenizer(string s, char del)
{
    stringstream ss(s);
    string word;
    while (!ss.eof()) {
        getline(ss, word, del);
        cout << word << endl;
    }
}
 
int main(int argc, char const* argv[])
{
    string a = "How do you do!";
    string b = "How$do$you$do!";
    // Takes only space separated C++ strings.
    simple_tokenizer(a);
    cout << endl;
    adv_tokenizer(b, '$');
    cout << endl;
    return 0;
}


Output : How 
     do 
     you
     do!
     

Time Complexity: O(n)

Auxiliary Space:O(n)

Where n is the length of the input string.

Method 2: Using C++ find() and substr() APIs.

Prerequisite: find function and substr().

This method is more robust and can parse a string with any delimiter, not just spaces(though the default behavior is to separate on spaces.) The logic is pretty simple to understand from the code below.

C++




#include <bits/stdc++.h>
using namespace std;
 
void tokenize(string s, string del = " ")
{
    int start, end = -1*del.size();
    do {
        start = end + del.size();
        end = s.find(del, start);
        cout << s.substr(start, end - start) << endl;
    } while (end != -1);
}
int main(int argc, char const* argv[])
{
    // Takes C++ string with any separator
    string a = "How$%do$%you$%do$%!";
    tokenize(a, "$%");
    cout << endl;
 
    return 0;
}


Output: How 
    do 
    you
    do
    !

Time Complexity: O(n)

Auxiliary Space:O(1)

Where n is the length of the input string.

Method 3: Using  temporary string

If you are given that the length of the delimiter is 1, then you can simply use a temp string to split the string. This will save the function overhead time in the case of method 2.

C++




#include <iostream>
using namespace std;
 
void split(string str, char del){
    // declaring temp string to store the curr "word" upto del
      string temp = "";
   
      for(int i=0; i<(int)str.size(); i++){
        // If cur char is not del, then append it to the cur "word", otherwise
          // you have completed the word, print it, and start a new word.
         if(str[i] != del){
            temp += str[i];
        }
          else{
            cout << temp << " ";
              temp = "";
        }
    }
       
      cout << temp;
}
 
int main() {
 
    string str = "Lazyroar_for_Lazyroar";    // string to be split
     char del = '_';    // delimiter around which string is to be split
   
      split(str, del);
     
    return 0;
}


Output

Lazyroar for Lazyroar

Time complexity : O(n)

Auxiliary Space: O(n)

In Java : 
In Java, split() is a method in String class. 

// expregexp is the delimiting regular expression; 
// limit is the number of returned strings
public String[] split(String regexp, int limit);

// We can call split() without limit also
public String[] split(String regexp)

Java




// A Java program for splitting a string
// using split()
import java.io.*;
public class Test
{
    public static void main(String args[])
    {
        String Str = new String("Geeks-for-Geeks");
 
        // Split above string in at-most two strings 
        for (String val: Str.split("-", 2))
            System.out.println(val);
 
        System.out.println("");
   
        // Splits Str into all possible tokens
        for (String val: Str.split("-"))
            System.out.println(val);
    }
}


Output: 

Geeks
for-Geeks

Geeks
for
Geeks

Time complexity : O(n)
Auxiliary Space: O(1)

In Python: 
The split() method in Python returns a list of strings after breaking the given string by the specified separator.  

 
  // regexp is the delimiting regular expression; 
  // limit is limit the number of splits to be made 
  str.split(regexp = "", limit = string.count(str))  

Python3




line = "Geek1 \nGeek2 \nGeek3"
print(line.split())
print(line.split(' ', 1))


Output: 

['Geek1', 'Geek2', 'Geek3']
['Geek1', '\nGeek2 \nGeek3'] 

Time Complexity : O(N), since it just traverse through the string finding all whitespace.

Auxiliary Space : O(1), since no extra space has been used.

This article is contributed by Aarti_Rathi and Aditya Chatterjee. If you like Lazyroar and would like to contribute, you can also write an article and mail your article to review-team@neveropen.co.za. See your article appearing on the Lazyroar main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above. 

Dominic Rubhabha Wardslaus
Dominic Rubhabha Wardslaushttps://neveropen.dev
infosec,malicious & dos attacks generator, boot rom exploit philanthropist , wild hacker , game developer,
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