In this article, we will see how to create a function that invokes each provided function with the arguments it receives using JavaScript.
It helps in reducing the effort of creating the same instance of code again and again. In this article let us see how to create a function that invokes each provided function with the arguments it receives and returns a value in JavaScript.
Functions can be defined in two ways:
Syntax:
function <function_name>(arg_1,arg_2,...)
{
<set of instructions>;
}
//INVOKER
var returned_value= function_name(arguments);
OR
var function_name = function(arg_1,arg_2,...)
{
<set of instructions>;
}
// INVOKER
var returned_value = function_name(arguments);
Below are the examples that help us to understand the problem easily.
Example 1: Function to separate even and odd numbers in an array. The findEven and findOdd functions take the same arguments by the segregateEvenodd function and are invoked in the segregateEvenodd function.
Javascript
<script> // Defined array var ar = [1, 2, 2, 3, 4, 5, 6, 6, 7, 8, 8, 8]; function findEven(ar){ var res1 = []; for (let geek = 0; geek < ar.length; geek++) { if (ar[geek] % 2 === 0) { res1.push(ar[geek]); } } return res1; } function findOdd(ar){ var res2 = []; for (let geek = 0; geek < ar.length; geek++) { if (ar[geek] % 2 === 1) { res2.push(ar[geek]); } } return res2; } function segregateEvenOdd(ar) { // Invoking findEven and findOdd functions var even = findEven(ar); var odd = findOdd(ar); console.log("Before Segregation: "); console.log(ar); console.log("After Segregation: "); console.log("Even integers: " + even); console.log("Odd integers: " + odd); } // Invoker segregateEvenOdd(ar); </script> |
Output:
"Before Segregation: " [1, 2, 2, 3, 4, 5, 6, 6, 7, 8, 8, 8] "After Segregation: " "Even integers: 2,2,4,6,6,8,8,8" "Odd integers: 1,3,5,7"
Example 2: Function to find minimum and maximum in an array. The findMin and findMax functions take the same arguments by the FindMinMax function and are invoked in the FindMinMax function.
Javascript
<script> // Defined array var ar = [20, 30, 40, 50, 60, -20, -40, 90, 100]; function findMin(ar) { var res1 = Number.MAX_VALUE;; for (let geek = 0; geek < ar.length; geek++) { if (ar[geek] < res1) { res1 = ar[geek]; } } return res1; } function findMax(ar) { var res2 = Number.MIN_VALUE; for (let geek = 0; geek < ar.length; geek++) { if (ar[geek] > res2) { res2 = ar[geek]; } } return res2; } function FindMinMax(ar) { // Invoking findMin and findMax functions var min = findMin(ar); var max = findMax(ar); console.log("Given array : "); console.log(ar); console.log("Minimum in the array: " + min); console.log("Maximum in the array: " + max); } // Invoker FindMinMax(ar); </script> |
Output:
"Given array : " [20, 30, 40, 50, 60, -20, -40, 90, 100] "Minimum in the array: -40" "Maximum in the array: 100"
