The task is to validate the IP address of both IPv4 as well as IPv6. Here we are going to use RegExp to solve the problem.
Approach 1:
- RegExp: Which split the IP address on. (dot) and check for each element whether they are valid or not(0-255).
Example 1: This example uses the approach discussed above.
html
<h1 style="color:green;"> neveropen </h1> <p id="GFG_UP"></p> <button onclick="GFG_Fun()"> click here </button> <p id="GFG_DOWN"></p> <script> var up = document.getElementById('GFG_UP'); var down = document.getElementById('GFG_DOWN'); var addr = '172.169.43.1'; up.innerHTML = "Click on the button to validate the IP Address.<br>" + addr; function GFG_Fun() { down.innerHTML = /^(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$/.test(addr); } </script> |
Output:
How to check for IP address using regular expression in javascript?
Approach 2:
- RegExp: Split the IP address on :(colon) and check for each element whether they are valid or not(0000-ffff).
Example 2: This example using the approach discussed above.
html
<h1 style="color:green;"> neveropen </h1> <p id="GFG_UP"></p> <button onclick="GFG_Fun()"> click here </button> <p id="GFG_DOWN"></p> <script> var up = document.getElementById('GFG_UP'); var down = document.getElementById('GFG_DOWN'); var addr = '2001:0db8:0000:0000:0000:ff00:0042:8329'; up.innerHTML = "Click on the button to validate the IP Address.<br>" + addr; function GFG_Fun() { down.innerHTML = /^[a-fA-F0-9]{1, 4}\:[a-fA-F0-9]{1, 4}\:[a-fA-F0-9]{1, 4}\:[a-fA-F0-9]{1, 4}\:[a-fA-F0-9]{1, 4}\:[a-fA-F0-9]{1, 4}\:[a-fA-F0-9]{1, 4}\:[a-fA-F0-9]{1, 4}$/.test(addr); } </script> |
Output:
How to check for IP address using regular expression in javascript?
