Given a number N, the task is to find Nth Heptacontagon number.
A Heptacontagon number is class of figurate number. It has 70 – sided polygon called heptacontagon. The N-th heptacontagon number count’s the 70 number of dots and all others dots are surrounding with a common sharing corner and make a pattern. The first few heptacontagonol numbers are 1, 70, 207, 412 …
Examples:
Input: N = 2
Output: 70
Explanation:
The second heptacontagonol number is 70.
Input: N = 3
Output: 207
Approach: The N-th heptacontagon number is given by the formula:
- Nth term of s sided polygon =
- Therefore Nth term of 70 sided polygon is
Below is the implementation of the above approach:
C++
// C++ program for above approach#include <bits/stdc++.h>using namespace std;// Finding the nth heptacontagon numberint heptacontagonNum(int n){ return (68 * n * n - 66 * n) / 2;}// Driver codeint main(){ int N = 3; cout << "3rd heptacontagon Number is = " << heptacontagonNum(N); return 0;}// This code is contributed by shivanisinghss2110 |
C
// C program for above approach#include <stdio.h>#include <stdlib.h>// Finding the nth heptacontagon Numberint heptacontagonNum(int n){ return (68 * n * n - 66 * n) / 2;}// Driver codeint main(){ int N = 3; printf("3rd heptacontagon Number is = %d", heptacontagonNum(N)); return 0;} |
Java
// Java program for the above approachclass GFG{// Finding the nth heptacontagon number static int heptacontagonNum(int n) { return (68 * n * n - 66 * n) / 2; } // Driver Codepublic static void main(String[] args){ int N = 3; System.out.println("3rd heptacontagon Number is = " + heptacontagonNum(N));}}// This code is contributed by rutvik_56 |
Python3
# Python3 program for above approach# Finding the nth heptacontagon Numberdef heptacontagonNum(n): return (68 * n * n - 66 * n) // 2;# Driver codeN = 3;print("3rd heptacontagon Number is =", heptacontagonNum(N));# This code is contributed by Akanksha_Rai |
C#
// C# program for the above approachusing System;class GFG{// Finding the nth heptacontagon number static int heptacontagonNum(int n) { return (68 * n * n - 66 * n) / 2; } // Driver Codepublic static void Main(){ int N = 3; Console.Write("3rd heptacontagon Number is = " + heptacontagonNum(N));}}// This code is contributed by Akanksha_Rai |
Javascript
<script>// JavaScript program for above approach// Finding the nth heptacontagon numberfunction heptacontagonNum(n){ return (68 * n * n - 66 * n) / 2;}// Driver codevar N = 3; document.write("3rd heptacontagon Number is = " + heptacontagonNum(N));</script> |
Output:
3rd heptacontagon Number is = 207
Time Complexity: O(1)
Auxiliary Space: O(1)
Reference: https://en.wikipedia.org/wiki/Heptacontagon
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