Given an integer N, the task is to generate random passwords of length N of easy, medium and strong level each.
Easy level Password: Consists of only numbers or letters. Medium level Password: Consists of Letters as well as numbers. Strong level Password – Consists of Letters, numbers, and/or special characters.
Examples:
Input: N = 5 Output: Easy level password (only numbers): 98990 Easy password (only letters): tpFEQ Medium level password: b3bC8 Strong level password: 7`74n Input: N = 7 Output: Easy level password (only numbers): 7508730 Easy level password (only letters): mDzKCjN Medium level password: 4Z05s66 Strong level password: 2384Qu9
Approach: Follow the steps below to solve the problem:
- For each password level, iterate through the given length.
- To generate each password, randomly assign characters and numbers using Random Number Generation based on the password level.
Below is the implementation of the above approach:
C
// C program to generate// password of given length#include <stdio.h>#include <stdlib.h>#include <time.h>// Function to generate easy level// password with numbersvoid easylevelpassnumbers(int n){ int i; // Random character generation // setting the seed as TIME srand(time(NULL)); printf("Easy level password " "(only numbers): "); for (i = 0; i < n; i++) { // rand() to assign random // characters in the password printf("%d", rand() % 10); } printf("\n");}// Function to generate easy level// password with lettersvoid easylevelpassletters(int n){ int i, d; printf("Easy level password" " (only letters): "); for (i = 0; i < n; i) { d = rand() % 123; if ((d >= 65 && d <= 90) || d >= 97) { printf("%c", (char)d); i++; } } printf("\n");}// Function to generate random// medium level passwordvoid midlevelpass(int n){ int i, d; printf("Medium level password: "); for (i = 0; i < n; i++) { d = rand() % 123; // Random alphabetic characters if ((d >= 65 && d <= 90) || d >= 97) { printf("%c", (char)d); } else { // Random digits printf("%d", d % 10); } } printf("\n");}// Function to generate strong// level passwordvoid stronglevelpass(int n){ int i, d; printf("Strong level password: "); for (i = 0; i < n; i++) { d = rand() % 200; // Random special characters if (d >= 33 && d <= 123) { printf("%c", (char)d); } else { // Random digits printf("%d", d % 10); } } printf("\n");}// Driver Codeint main(){ int n = 5; easylevelpassnumbers(n); easylevelpassletters(n); midlevelpass(n); stronglevelpass(n);} |
Python3
# Python program to generate# password of given lengthimport randomimport string# Function to generate easy level password with numbersdef easy_level_pass_numbers(n): # Random character generation print("Easy level password (only numbers): ", end="") for i in range(n): # Random digits print(random.randint(0, 9), end="") print()# Function to generate easy level password with lettersdef easy_level_pass_letters(n): # Random character generation print("Easy level password (only letters): ", end="") for i in range(n): # Random alphabetic characters print(random.choice(string.ascii_letters), end="") print()# Function to generate random medium level passworddef mid_level_pass(n): # Random character generation print("Medium level password: ", end="") for i in range(n): # Random alphabetic characters or digits print(random.choice(string.ascii_letters + string.digits), end="") print()# Function to generate strong level passworddef strong_level_pass(n): # Random character generation print("Strong level password: ", end="") for i in range(n): # Random special characters or digits print(random.choice(string.ascii_letters + string.digits + string.punctuation), end="") print()# Driver Codeif __name__ == '__main__': n = 5 easy_level_pass_numbers(n) easy_level_pass_letters(n) mid_level_pass(n) strong_level_pass(n)# Contributed by adityasha4x71 |
Output:
Easy level password (only numbers): 36707 Easy level password (only letters): cQWxF Medium level password: 56G4w Strong level password: 83s20
Time Complexity: O(N)
Auxiliary Space: O(N)
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