Given a matrix mat[][] containing the characters Z, P and * where Z is a zombie, P is a plant and * is a bare land. Given that a zombie can attack a plant if the plant is adjacent to the zombie (total, 8 adjacent cells are possible). The task is to print the number of plants that are safe from the zombies.
Examples:Â
Input: mat[] = { "**P*", "*Z**", "*Z**", "***P" } Output: 1 Input: mat[] = { "**P*P", "*Z**", "*P**", "***P" } Output: 2
Approach: Traverse the matrix element by element, if the current element is a plant i.e., mat[i][j] = ‘P’ then check if the plant is surrounded by any zombie (in all the 8 adjacent cells). If the plant is safe, then update count = count + 1. Print the count in the end.
Below is the implementation of the above approach:Â
C++
// C++ implementation of the approach #include <iostream> using namespace std; Â
// Function that returns true if mat[i][j] is a zombie bool isZombie( int i, int j, int r, int c, string mat[]) {     if (i < 0 || j < 0 || i >= r || j >= c         || mat[i][j] != 'Z' )         return false ; Â
    return true ; } Â
// Function to return the count of plants // that survived from the zombies attack int Plant_Vs_Zombies(string mat[], int row, int col) { Â Â Â Â int i, j, count = 0; Â
    for (i = 0; i < row; i++) {         for (j = 0; j < col; j++) { Â
            // If current cell is a plant             if (mat[i][j] == 'P' ) { Â
                // If current plant is safe from zombies                 if (!isZombie(i - 1, j - 1, row, col, mat)                     && !isZombie(i - 1, j, row, col, mat)                     && !isZombie(i - 1, j + 1, row, col, mat)                     && !isZombie(i, j - 1, row, col, mat)                     && !isZombie(i, j, row, col, mat)                     && !isZombie(i, j + 1, row, col, mat)                     && !isZombie(i + 1, j - 1, row, col, mat)                     && !isZombie(i + 1, j, row, col, mat)                     && !isZombie(i + 1, j + 1, row, col, mat)) {                     count++;                 }             }         }     } Â
    return count; } Â
// Driver Code int main() {     // Input matrix     string mat[] = { "**P*" , "*Z**" , "*Z**" , "***P" }; Â
    // Rows and columns of the matrix     int row = sizeof (mat) / sizeof (mat[0]);     int col = mat[0].length(); Â
    // Total plants survived     cout << Plant_Vs_Zombies(mat, row, col); } |
Java
// Java implementation of the approach. Â
class GfG { Â
    // Function that returns true if     // mat[i][j] is a zombie     static boolean isZombie( int i, int j, int r,                             int c, String mat[])     {         if (i < 0 || j < 0 || i >= r || j >= c             || mat[i].charAt(j) != 'Z' )             return false ;              return true ;     }          // Function to return the count of plants     // that survived from the zombies attack     static int Plant_Vs_Zombies(String mat[],                             int row, int col)     {         int i, j, count = 0 ;              for (i = 0 ; i < row; i++)         {             for (j = 0 ; j < col; j++)             {                      // If current cell is a plant                 if (mat[i].charAt(j) == 'P' )                 {                          // If current plant is safe from zombies                     if (!isZombie(i - 1 , j - 1 , row, col, mat)                         && !isZombie(i - 1 , j, row, col, mat)                         && !isZombie(i - 1 , j + 1 , row, col, mat)                         && !isZombie(i, j - 1 , row, col, mat)                         && !isZombie(i, j, row, col, mat)                         && !isZombie(i, j + 1 , row, col, mat)                         && !isZombie(i + 1 , j - 1 , row, col, mat)                         && !isZombie(i + 1 , j, row, col, mat)                         && !isZombie(i + 1 , j + 1 , row, col, mat)) {                         count++;                     }                 }             }         }         return count;     } Â
    // Driver code     public static void main(String []args)     {                  // Input matrix         String[] mat = { "**P*" , "*Z**" , "*Z**" , "***P" };              // Rows and columns of the matrix         int row = mat.length;         int col = mat[ 0 ].length();              // Total plants survived         System.out.println(Plant_Vs_Zombies(mat, row, col));     } } Â
// This code is contributed by Rituraj Jain |
Python3
# Python3 implementation of the approach. Â
# Function that returns true if # mat[i][j] is a zombie def isZombie(i, j, r, c, mat): Â
    if (i < 0 or j < 0 or i > = r or         j > = c or mat[i][j] ! = 'Z' ):         return True ; Â
    return False ; Â
# Function to return the count of plants # that survived from the zombies attack def Plant_Vs_Zombies(mat, row, col): Â
    count = 0 ; Â
    for i in range (row):         for j in range (col): Â
            # If current cell is a plant             if (mat[i][j] = = 'P' ): Â
                # If current plant is safe from zombies                 if (isZombie(i - 1 , j - 1 , row, col, mat) and                     isZombie(i - 1 , j, row, col, mat) and                     isZombie(i - 1 , j + 1 , row, col, mat) and                     isZombie(i, j - 1 , row, col, mat) and                     isZombie(i, j, row, col, mat) and                     isZombie(i, j + 1 , row, col, mat) and                     isZombie(i + 1 , j - 1 , row, col, mat) and                     isZombie(i + 1 , j, row, col, mat) and                     isZombie(i + 1 , j + 1 , row, col, mat)):                     count + = 1 ;     return count; Â
# Driver code Â
# Input matrix mat = [ "**P*" , "*Z**" , "*Z**" , "***P" ]; Â
# Rows and columns of the matrix row = len (mat); col = len (mat[ 0 ]); Â
# Total plants survived print (Plant_Vs_Zombies(mat, row, col)); Â
# This code is contributed by mits |
C#
// C# implementation of the approach. using System; Â
class GfG { Â
    // Function that returns true if     // mat[i][j] is a zombie     static bool isZombie( int i, int j, int r,                             int c, String []mat)     {         if (i < 0 || j < 0 || i >= r || j >= c             || mat[i][j] != 'Z' )             return false ;              return true ;     }          // Function to return the count of plants     // that survived from the zombies attack     static int Plant_Vs_Zombies(String []mat,                             int row, int col)     {         int i, j, count = 0;              for (i = 0; i < row; i++)         {             for (j = 0; j < col; j++)             {                      // If current cell is a plant                 if (mat[i][j] == 'P' )                 {                          // If current plant is safe from zombies                     if (!isZombie(i - 1, j - 1, row, col, mat)                         && !isZombie(i - 1, j, row, col, mat)                         && !isZombie(i - 1, j + 1, row, col, mat)                         && !isZombie(i, j - 1, row, col, mat)                         && !isZombie(i, j, row, col, mat)                         && !isZombie(i, j + 1, row, col, mat)                         && !isZombie(i + 1, j - 1, row, col, mat)                         && !isZombie(i + 1, j, row, col, mat)                         && !isZombie(i + 1, j + 1, row, col, mat))                     {                         count++;                     }                 }             }         }         return count;     } Â
    // Driver code     public static void Main(String []args)     {                  // Input matrix         String[] mat = { "**P*" , "*Z**" , "*Z**" , "***P" };              // Rows and columns of the matrix         int row = mat.Length;         int col = mat[0].Length;              // Total plants survived         Console.WriteLine(Plant_Vs_Zombies(mat, row, col));     } } Â
// This code contributed by Rajput-Ji |
PHP
<?php // PHP implementation of the approach. Â
// Function that returns true if // mat[i][j] is a zombie function isZombie( $i , $j , $r , $c , $mat ) { Â Â Â Â if ( $i < 0 || $j < 0 || $i >= $r || Â Â Â Â Â Â Â Â $j >= $c || $mat [ $i ][ $j ] != 'Z' ) Â Â Â Â Â Â Â Â return false; Â
    return true; } Â
// Function to return the count of plants // that survived from the zombies attack function Plant_Vs_Zombies( $mat , $row , $col ) { Â Â Â Â $i ; $j ; $count = 0; Â
    for ( $i = 0; $i < $row ; $i ++)     {         for ( $j = 0; $j < $col ; $j ++)         { Â
            // If current cell is a plant             if ( $mat [ $i ][ $j ] == 'P' )             { Â
                // If current plant is safe from zombies                 if (!isZombie( $i - 1, $j - 1, $row , $col , $mat ) &&                     !isZombie( $i - 1, $j , $row , $col , $mat ) &&                     !isZombie( $i - 1, $j + 1, $row , $col , $mat ) &&                     !isZombie( $i , $j - 1, $row , $col , $mat ) &&                     !isZombie( $i , $j , $row , $col , $mat ) &&                     !isZombie( $i , $j + 1, $row , $col , $mat ) &&                     !isZombie( $i + 1, $j - 1, $row , $col , $mat ) &&                     !isZombie( $i + 1, $j , $row , $col , $mat ) &&                     !isZombie( $i + 1, $j + 1, $row , $col , $mat ))                 {                     $count ++;                 }             }         }     }     return $count ; } Â
// Driver code Â
// Input matrix $mat = array ( "**P*" , "*Z**" , "*Z**" , "***P" ); Â
// Rows and columns of the matrix $row = sizeof( $mat ); $col = strlen ( $mat [0]); Â
// Total plants survived echo (Plant_Vs_Zombies( $mat , $row , $col )); Â
// This code is contributed by Code_Mech. ?> |
Javascript
<script> Â
// Javascript implementation of the approach. Â
// Function that returns true if // mat[i][j] is a zombie function isZombie(i, j, r, c, mat) {     if (i < 0 || j < 0 || i >= r ||        j >= c || mat[i][j] != 'Z' )         return false ;        return true ; }    // Function to return the count of plants // that survived from the zombies attack function Plant_Vs_Zombies(mat, row, col) {     let i, j, count = 0;        for (i = 0; i < row; i++)     {         for (j = 0; j < col; j++)         {                          // If current cell is a plant             if (mat[i][j] == 'P' )             {                                  // If current plant is safe from zombies                 if (!isZombie(i - 1, j - 1, row, col, mat) &&                     !isZombie(i - 1, j, row, col, mat) &&                     !isZombie(i - 1, j + 1, row, col, mat) &&                     !isZombie(i, j - 1, row, col, mat) &&                     !isZombie(i, j, row, col, mat) &&                     !isZombie(i, j + 1, row, col, mat) &&                     !isZombie(i + 1, j - 1, row, col, mat) &&                     !isZombie(i + 1, j, row, col, mat) &&                     !isZombie(i + 1, j + 1, row, col, mat))                 {                     count++;                 }             }         }     }     return count; } Â
// Driver code Â
// Input matrix let mat = [ "**P*" , "*Z**" , "*Z**" , "***P" ]; Â
// Rows and columns of the matrix let row = mat.length; let col = mat[0].length; Â
// Total plants survived document.write(Plant_Vs_Zombies(mat, row, col)); Â
// This code is contributed by mukesh07 Â
</script> |
1
Complexity Analysis:
- Time Complexity: O(N×N)
- Auxiliary Space: O(1)
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