Given a singly circular linked list of nodes. The task is to find the smallest and largest elements in the circular linked list.
Examples:
Input : List = 99->11->22->33->44->55->66 Output : Minimum = 11, Maximum = 99 Input : List = 12->11->9->33->125->6->99 Output : Minimum = 6, Maximum = 125
The idea is to traverse the circular linked list while the last node is not reached and initialize the max and min variables to INT_MIN and INT_MAX respectively. After that, check the condition that if the max value is less than the head value, then the head value is assigned to the max or if the min value is greater than the head value, then the head value is assigned to the min, otherwise the head point to the next node. Continue this process until the last node.
Algorithm:
Step 1: Create a function named “printMinMax” that takes the head node of a circular linked list as an input parameter.
Step 2: Create two integer variables min and max and initialize them to Integer.MAX_VALUE and Integer.MIN_VALUE, respectively.
Step 3: Define a pointer “current” and initialize it with the head node.
Step 4: Start a while loop till current.next is not equal to null.
a. In each iteration of the while loop, compare the data of the current node with the values of min and max. If the data is lesser than the value of min, assign the data to the min variable. If the data is greater than the value of max, assign the data to the max variable.
b. Update the current pointer to the next node.
Step 5: Now after the while loop, print the values of min and max statement.
Step 6: Create a function named “insertNode” which takes a head node of a circular linked list and a data value to be inserted into the linked list an input parameter.
Step 7: Create a new node with the given data value and check whether the node is created successfully or not.
Step 8: Assign the new node’s next pointer to the node itself if the linked list is empty, and then return the new node as the head node.
Step 9: If the linked list is not empty, traverse the linked list until the last node using a while loop.
Step 10: Give the head node the new node’s next pointer and then give it back.
Step 11: Create a function named “displayList” which take the head node of a circular linked list and prints the values of all the nodes in the linked list as an input parameter.
Step 12: Use a do-while loop to iteratively navigate the linked list until you reach the head node once more after initializing a pointer with the head node.
Step 13: Print the value of the current node using the System on each iteration of the do-while loop. out. move the current pointer to the following node and use the print statement
Below is the implementation of the above approach:
C++
// C++ program to find minimum and maximum // value from singly circular linked list #include <bits/stdc++.h> using namespace std; // structure for a node struct Node { int data; struct Node* next; }; // Function to print minimum and maximum // nodes of the circular linked list void printMinMax( struct Node** head) { // check list is empty if (*head == NULL) { return ; } // pointer for traversing struct Node* current; // initialize head to current pointer current = *head; // initialize max int value to min // initialize min int value to max int min = INT_MAX, max = INT_MIN; // While last node is not reached do { // If current node data is lesser for min // then replace it if (current->data < min) { min = current->data; } // If current node data is greater for max // then replace it if (current->data > max) { max = current->data; } current = current->next; } while (current != *head); cout << "\nMinimum = " << min << ", Maximum = " << max; } // Function to insert a node at the end of // a Circular linked list void insertNode( struct Node** head, int data) { struct Node* current = *head; // Create a new node struct Node* newNode = new Node; // check node is created or not if (!newNode) { printf ( "\nMemory Error\n" ); return ; } // insert data into newly created node newNode->data = data; // check list is empty // if not have any node then // make first node it if (*head == NULL) { newNode->next = newNode; *head = newNode; return ; } // if list have already some node else { // move first node to last node while (current->next != *head) { current = current->next; } // put first or head node address // in new node link newNode->next = *head; // put new node address into // last node link(next) current->next = newNode; } } // Function to print the Circular linked list void displayList( struct Node* head) { struct Node* current = head; // if list is empty simply show message if (head == NULL) { printf ( "\nDisplay List is empty\n" ); return ; } // traverse first to last node else { do { printf ( "%d " , current->data); current = current->next; } while (current != head); } } // Driver Code int main() { struct Node* Head = NULL; insertNode(&Head, 99); insertNode(&Head, 11); insertNode(&Head, 22); insertNode(&Head, 33); insertNode(&Head, 44); insertNode(&Head, 55); insertNode(&Head, 66); cout << "Initial List: " ; displayList(Head); printMinMax(&Head); return 0; } |
Java
// Java program to find minimum and maximum // value from singly circular linked list class GFG { // structure for a node static class Node { int data; Node next; }; // Function to print minimum and maximum // nodes of the circular linked list static void printMinMax(Node head) { // check list is empty if (head == null ) { return ; } // pointer for traversing Node current; // initialize head to current pointer current = head; // initialize max int value to min // initialize min int value to max int min = Integer.MAX_VALUE, max = Integer.MIN_VALUE; // While last node is not reached while (current.next != head) { // If current node data is lesser for min // then replace it if (current.data < min) { min = current.data; } // If current node data is greater for max // then replace it if (current.data > max) { max = current.data; } current = current.next; } System.out.println( "\nMinimum = " + min + ", Maximum = " + max); } // Function to insert a node at the end of // a Circular linked list static Node insertNode(Node head, int data) { Node current = head; // Create a new node Node newNode = new Node(); // check node is created or not if (newNode == null ) { System.out.printf( "\nMemory Error\n" ); return null ; } // insert data into newly created node newNode.data = data; // check list is empty // if not have any node then // make first node it if (head == null ) { newNode.next = newNode; head = newNode; return head; } // if list have already some node else { // move first node to last node while (current.next != head) { current = current.next; } // put first or head node address // in new node link newNode.next = head; // put new node address into // last node link(next) current.next = newNode; } return head; } // Function to print the Circular linked list static void displayList(Node head) { Node current = head; // if list is empty simply show message if (head == null ) { System.out.printf( "\nDisplay List is empty\n" ); return ; } // traverse first to last node else { do { System.out.printf( "%d " , current.data); current = current.next; } while (current != head); } } // Driver Code public static void main(String args[]) { Node Head = null ; Head=insertNode(Head, 99 ); Head=insertNode(Head, 11 ); Head=insertNode(Head, 22 ); Head=insertNode(Head, 33 ); Head=insertNode(Head, 44 ); Head=insertNode(Head, 55 ); Head=insertNode(Head, 66 ); System.out.println( "Initial List: " ); displayList(Head); printMinMax(Head); } } // This code is contributed by Arnab Kundu |
Python3
# Python3 program to find minimum and maximum # value from singly circular linked list # structure for a node class Node: def __init__( self ): self .data = 0 self . next = None # Function to print minimum and maximum # nodes of the circular linked list def printMinMax(head): # check list is empty if (head = = None ): return ; # initialize head to current pointer current = head; # initialize max int value to min # initialize min int value to max min = 1000000000 max = - 1000000000 ; # While last node is not reached while True : # If current node data is lesser for min # then replace it if (current.data < min ): min = current.data; # If current node data is greater for max # then replace it if (current.data > max ): max = current.data; current = current. next ; if (current = = head): break print ( 'Minimum = {}, Maximum = {}' . format ( min , max )) # Function to insert a node at the end of # a Circular linked list def insertNode(head, data): current = head; # Create a new node newNode = Node() # check node is created or not if not newNode: print ( "\nMemory Error" ); return head # insert data into newly created node newNode.data = data; # check list is empty # if not have any node then # make first node it if (head = = None ): newNode. next = newNode; head = newNode; return head # if list have already some node else : # move first node to last node while (current. next ! = head): current = current. next ; # put first or head node address # in new node link newNode. next = head; # put new node address into # last node link(next) current. next = newNode; return head # Function to print the Circular linked list def displayList(head): current = head; # if list is empty simply show message if (head = = None ): print ( "\nDisplay List is empty" ); return ; # traverse first to last node else : while True : print (current.data, end = ' ' ); current = current. next ; if (current = = head): break print () # Driver Code if __name__ = = '__main__' : Head = None ; Head = insertNode(Head, 99 ); Head = insertNode(Head, 11 ); Head = insertNode(Head, 22 ); Head = insertNode(Head, 33 ); Head = insertNode(Head, 44 ); Head = insertNode(Head, 55 ); Head = insertNode(Head, 66 ); print ( "Initial List: " , end = '') displayList(Head); printMinMax(Head); # This code is contributed by rutvik_56 |
C#
// C# program to find minimum and maximum // value from singly circular linked list using System; class GFG { // structure for a node public class Node { public int data; public Node next; }; // Function to print minimum and maximum // nodes of the circular linked list static void printMinMax(Node head) { // check list is empty if (head == null ) { return ; } // pointer for traversing Node current; // initialize head to current pointer current = head; // initialize max int value to min // initialize min int value to max int min = int .MaxValue, max = int .MinValue; // While last node is not reached while (current.next != head) { // If current node data is lesser for min // then replace it if (current.data < min) { min = current.data; } // If current node data is greater for max // then replace it if (current.data > max) { max = current.data; } current = current.next; } Console.WriteLine( "\nMinimum = " + min + ", Maximum = " + max); } // Function to insert a node at the end of // a Circular linked list static Node insertNode(Node head, int data) { Node current = head; // Create a new node Node newNode = new Node(); // check node is created or not if (newNode == null ) { Console.Write( "\nMemory Error\n" ); return null ; } // insert data into newly created node newNode.data = data; // check list is empty // if not have any node then // make first node it if (head == null ) { newNode.next = newNode; head = newNode; return head; } // if list have already some node else { // move first node to last node while (current.next != head) { current = current.next; } // put first or head node address // in new node link newNode.next = head; // put new node address into // last node link(next) current.next = newNode; } return head; } // Function to print the Circular linked list static void displayList(Node head) { Node current = head; // if list is empty simply show message if (head == null ) { Console.Write( "\nDisplay List is empty\n" ); return ; } // traverse first to last node else { do { Console.Write( "{0} " , current.data); current = current.next; } while (current != head); } } // Driver Code public static void Main() { Node Head = null ; Head=insertNode(Head, 99); Head=insertNode(Head, 11); Head=insertNode(Head, 22); Head=insertNode(Head, 33); Head=insertNode(Head, 44); Head=insertNode(Head, 55); Head=insertNode(Head, 66); Console.WriteLine( "Initial List: " ); displayList(Head); printMinMax(Head); } } /* This code contributed by PrinciRaj1992 */ |
Javascript
<script> // javascript program to find minimum and maximum // value from singly circular linked list // structure for a node class Node { constructor() { this .data = 0; this .next = null ; } } // Function to print minimum and maximum // nodes of the circular linked list function printMinMax(head) { // check list is empty if (head == null ) { return ; } // pointer for traversing var current; // initialize head to current pointer current = head; // initialize max var value to min // initialize min var value to max var min = Number.MAX_VALUE, max = Number.MIN_VALUE; // While last node is not reached while (current.next != head) { // If current node data is lesser for min // then replace it if (current.data < min) { min = current.data; } // If current node data is greater for max // then replace it if (current.data > max) { max = current.data; } current = current.next; } document.write( "<br/>Minimum = " + min + ", Maximum = " + max); } // Function to insert a node at the end of // a Circular linked list function insertNode(head , data) { var current = head; // Create a new node var newNode = new Node(); // check node is created or not if (newNode == null ) { document.write( "<br/>Memory Error\n" ); return null ; } // insert data into newly created node newNode.data = data; // check list is empty // if not have any node then // make first node it if (head == null ) { newNode.next = newNode; head = newNode; return head; } // if list have already some node else { // move first node to last node while (current.next != head) { current = current.next; } // put first or head node address // in new node link newNode.next = head; // put new node address into // last node link(next) current.next = newNode; } return head; } // Function to print the Circular linked list function displayList(head) { var current = head; // if list is empty simply show message if (head == null ) { document.write( "<br/>Display List is empty<br/>" ); return ; } // traverse first to last node else { do { document.write(current.data+ " " ); current = current.next; } while (current != head); } } // Driver Code var Head = null ; Head = insertNode(Head, 99); Head = insertNode(Head, 11); Head = insertNode(Head, 22); Head = insertNode(Head, 33); Head = insertNode(Head, 44); Head = insertNode(Head, 55); Head = insertNode(Head, 66); document.write( "Initial List: " ); displayList(Head); printMinMax(Head); // This code contributed by umadevi9616 </script> |
Initial List: 99 11 22 33 44 55 66 Minimum = 11, Maximum = 99
Complexity Analysis:
- Time Complexity: O(n), as we are using a loop to traverse n times. Where n is the number of nodes in the linked list.
- Auxiliary Space: O(1), as we are not using any extra space.
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