The worst case running time to search for an element in a balanced in a binary search tree with n2^n elements is
(A) 
(B)
(C)
(D)
(A)
A
(B)
B
(C)
C
(D)
D
Answer: (C)
Explanation:
Time taken to search an element is where h is the height of Binary Search Tree (BST). The growth of height of a balanced BST is logarithmic in terms of number of nodes. So the worst case time to search an element would be which is Which is which can be written as .
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