The d3.timeMondays() function in D3.js is used to return all the dates based on Monday in the given range of start and end date.
Syntax:
d3.timeMondays( start, end, step );
Parameters: This function accept three parameters as mentioned above and described below:
- Start: This parameter holds the given start date.
- end: This parameter holds the given end date.
- step: It is the optional parameter and the value used to skip dates.
Return Value: This function returns all the dates based on Monday.
Below programs illustrate the d3.timeMondays() function in D3.js:
Example 1:
<!DOCTYPE html> <html>   <head>     <title>         D3.js | d3.timeMondays() Function     </title>           <script src =     </script> </head>   <body>     <script>                   // Initialising start and end date         var start = new Date(2015, 07, 01);         var end = new Date(2015, 07, 30);                   // Calling the timeMondays() function         // without step value         var a = d3.timeMondays(start, end);                   // Getting the Monday dates         console.log(a);     </script> </body>   </html> |
Output:
["2015-08-02T18:30:00.000Z", "2015-08-09T18:30:00.000Z", "2015-08-16T18:30:00.000Z", "2015-08-23T18:30:00.000Z"]
Example 2:
<!DOCTYPE html> <html>   <head>     <title>         D3.js | d3.timeMondays() Function     </title>           <script src =     </script> </head>   <body>     <script>                   // Initialising start and end date         var start = new Date(2015, 07, 01);         var end = new Date(2015, 07, 30);                   // Calling the timeMondays() function         // with step value         var a = d3.timeMondays(start, end, 2);                   // Getting the Monday dates         console.log(a);     </script> </body>   </html>                    |
Output:
["2015-08-02T18:30:00.000Z", "2015-08-16T18:30:00.000Z"]
Reference: https://devdocs.io/d3~5/d3-time#timeMondays
