In this article, we will see how to create multiple copies of a string by using the multiplication operator(*). Python supports certain operations to be performed on a string, multiplication operator is one of them.
Method 1:
Simply using multiplication operator on the string to be copied with the required number of times it should be copied.
Syntax:
str2 = str1 * N
where str2 is the new string where you want to store the new string
str1 is the original string
N is the number of the times you want to copy the string.
After using multiplication operator we get a string as output
Example 1:
Python3
# Original stringa = "Geeks"# Multiply the string and store# it in a new stringb = a*3# Display the stringsprint(f"Original string is: {a}")print(f"New string is: {b}") |
Original string is: Geeks New string is: GeeksGeeksGeeks
Example 2:
Python3
# Initializing the original stringa = "Hello"n = 5# Multiplying the stringb = a*n# Print the stringsprint(f"Original string is: {a}")print(f"New string is: {b}") |
Original string is: Hello New string is: HelloHelloHelloHelloHello
Method 2: Copying a string multiple times given in a list
If we have a string as a list element, and we use the multiplication operator on the list we will get a new list that contains the same element copied specified number of times.
Syntax:
a = [“str1”] * N
a will be a list that contains str1 N number of times.
It is not necessary that the element we want to duplicate in a list has to be a string. Multiplication operator in a list can duplicate anything.
Example 3:
Python3
# Initialize the lista = ["Geeks"]# Number of copiesn = 3# Multiplying the list elementsb = a*n# print the listprint(f"Original list is: {a} ")print(f"List after multiplication is: {b}") |
Original list is: ['Geeks'] List after multiplication is: ['Geeks', 'Geeks', 'Geeks']
The time complexity of this code is O(n), where n is the number of copies of the original list.
The auxiliary space complexity of this code is also O(n), where n is the number of copies of the original list.
Example 4: Shorthand method for the same approach
Python3
# initializing a string with all True'sa = [True]*5print(a)# Initializing a list with all 0a = [0]*10print(a) |
[True, True, True, True, True] [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
METHOD 3:Using for
APPROACH:
The above code creates a new string by repeating the given string a specified number of times using a for loop.
ALGORITHM:
1.Initialize a variable string with the given string.
2.Initialize a variable n with the desired number of copies.
3.Initialize an empty string new_string.
4.Loop through n times using a for loop and for each iteration, concatenate the original string to the new_string.
5.Print the resulting new_string.
Python3
string = "Geeks"n = 3new_string = ""for i in range(n): new_string += stringprint(new_string) |
GeeksGeeksGeeks
Time Complexity:
The time complexity of the above code is O(n) because the for loop runs n times.
Space Complexity:
The space complexity of the above code is also O(n) because we are storing the resulting new_string in memory, which can grow up to n times the size of the original string.
