Given an integer N, where 
. The task is to print the count of pieces of a circle with N cuts where each cut passes through the centre of given circle.
Examples:
Input : N = 2 Output : 4 Input : N = 100 Output : 200
Approach: This problem can be easily solved with observation only. Since each cut passes through the centre, each cut creates two new pieces.
Let us see how above Intuition works.
- At first cut we have 2 different pieces of circle.
- At second cut we have 2 new different pieces from previous 2 pieces of circle.
- At third cut we have again 2 new different pieces from any of previous 2 pieces which are opposite to each other.
In this way, we proceed with N cuts to get the count of total pieces after N cuts.
Below is the implementation of above approach:
C++
// C++ program to find number of pieces// of circle after N cuts#include <bits/stdc++.h>using namespace std;// Function to find number of pieces// of circle after N cutsint countPieces(int N){ return 2 * N;}// Driver programint main(){ int N = 100; cout << countPieces(N); return 0;} |
Java
// Java program to find number of pieces// of circle after N cutsimport java.util.*;class solution{// Function to find number of pieces// of circle after N cutsstatic int countPieces(int N){ return 2 * N;}// Driver programpublic static void main(String args[]){ int N = 100; System.out.println(countPieces(N));}} |
Python3
# Python program to find number # of pieces of circle after N cuts # Function to find number of # pieces of circle after N cuts def countPieces(N): return 2 * N # Driver Code N = 100print(countPieces(N))# This code is contributed by# Sanjit_Prasad |
C#
// C# program to find number of pieces// of circle after N cutsclass solution{// Function to find number of pieces// of circle after N cutsstatic int countPieces(int N){ return 2 * N;}// Driver programstatic void Main(){ int N = 100; System.Console.WriteLine(countPieces(N));}}// This code is contributed by mits |
PHP
<?php// PHP program to find number of // pieces of circle after N cuts// Function to find number of pieces// of circle after N cutsfunction countPieces($N){ return 2 * $N;}// Driver Code$N = 100;echo countPieces($N);// This code is contributed by anuj_67?> |
Javascript
<script>// Javascript program to find number of pieces// of circle after N cuts// Function to find number of pieces// of circle after N cutsfunction countPieces(N){ return 2 * N;}// driver program let N = 100; document.write(countPieces(N)); </script> |
Output:
200
Time Complexity: O(1)
Auxiliary Space: O(1)
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