The isInterface() method of java.lang.Class class is used to check if this Class is an interface. The method returns true if this Class is an interface. It returns false otherwise.
Syntax:
public boolean isInterface()
Parameter: This method does not accept any parameter.
Return Value: This method returns true if this Class is an interface. It returns false otherwise.
Below programs demonstrate the isInterface() method.
Example 1:
Java
// Java program to demonstrate isInterface() method  public class Test {    public static void main(String[] args)        throws ClassNotFoundException    {          // returns the Class object for this class        Class myClass = Class.forName("Test");          System.out.println("Class represented by myClass: "                           + myClass.toString());          // Check if this class is an interface        // using isInterface() method        System.out.println("Is Test an interface: "                           + myClass.isInterface());    }} |
Output:
Class represented by myClass: class Test Is Test an interface: false
Example 2:
Java
// Java program to demonstrate isInterface() method  interface T {}  public class Test {    public static void main(String[] args)        throws ClassNotFoundException    {          // returns the Class object for this class        Class myClass = Class.forName("T");          // Check if T is an interface        // using isInterface() method        System.out.println("Is T an interface: "                           + myClass.isInterface());    }} |
Output:
Is T an interface: true
Reference: https://docs.oracle.com/javase/9/docs/api/java/lang/Class.html#isInterface–
