Given integers A, B, C, and D denoting the length of sides of a Cyclic Quadrilateral, the task is to find the circumradius i.e., the radius of circumcircle of the given cyclic quadrilateral.
Examples:
Input: A = 3, B = 4, C = 5, D= 6
Output: 3.29Input: A = 10, B = 30, C = 50, D = 20
Output: 27.78
Approach: Follow the steps below to solve the problem:
- Calculate the semiperimeter of the cyclic quadrilateral with sides A, B, C and D by using the equation:
- Now, using Parameshvara’s circumradius formula shown below, calculate the radius for the circumcircle:
Below is the implementation of the above approach:
C++14
// C++ program to find circumradius of // a cyclic quadrilateral using sides #include <bits/stdc++.h> using namespace std; // Function to return the circumradius // of a cyclic quadrilateral using sides double Circumradius( int a, int b, int c, int d) { // Find semiperimeter double s = (a + b + c + d) / 2.0; // Calculate the radius double radius = sqrt (((a * b) + (c * d)) * ((a * c) + (b * d)) * ((a * d) + (b * c)) / ((s - a) * (s - b) * (s - c) * (s - d))); return radius / 4; } // Driver Code int main() { int A = 3; int B = 4; int C = 5; int D = 6; // Function call double ans = Circumradius(A, B, C, D); // Print the radius cout << setprecision(3) << ans; return 0; } // This code is contributed by mohit kumar 29 |
Java
// Java program to find circumradius of // a cyclic quadrilateral using sides import java.util.*; class GFG{ // Function to return the circumradius // of a cyclic quadrilateral using sides static double Circumradius( int a, int b, int c, int d) { // Find semiperimeter double s = (a + b + c + d) / 2.0 ; // Calculate the radius double radius = Math.sqrt(((a * b) + (c * d)) * ((a * c) + (b * d)) * ((a * d) + (b * c)) / ((s - a) * (s - b) * (s - c) * (s - d))); return radius / 4 ; } // Driver Code public static void main(String[] args) { int A = 3 ; int B = 4 ; int C = 5 ; int D = 6 ; // Function call double ans = Circumradius(A, B, C, D); // Print the radius System.out.format( "%.2f" , ans); } } // This code is contributed by 29AjayKumar |
Python3
# Program to find Circumradius of # a cyclic quadrilateral using sides import math # Function to return the Circumradius # of a cyclic quadrilateral using sides def Circumradius(a, b, c, d): # Find semiperimeter s = (a + b + c + d) / 2 # Calculate the radius radius = ( 1 / 4 ) * math.sqrt(((a * b) + (c * d)) * ((a * c) + (b * d)) * ((a * d) + (b * c)) / ((s - a) * (s - b) * (s - c) * (s - d))) return radius # Driver Code # Given sides A = 3 B = 4 C = 5 D = 6 # Function Call ans = Circumradius(A, B, C, D) # Print the radius print ( round (ans, 2 )) |
C#
// C# program to find circumradius of // a cyclic quadrilateral using sides using System; class GFG{ // Function to return the circumradius // of a cyclic quadrilateral using sides static double Circumradius( int a, int b, int c, int d) { // Find semiperimeter double s = (a + b + c + d) / 2.0; // Calculate the radius double radius = Math.Sqrt(((a * b) + (c * d)) * ((a * c) + (b * d)) * ((a * d) + (b * c)) / ((s - a) * (s - b) * (s - c) * (s - d))); return radius / 4; } // Driver Code public static void Main(String[] args) { int A = 3; int B = 4; int C = 5; int D = 6; // Function call double ans = Circumradius(A, B, C, D); // Print the radius Console.Write( "{0:F2}" , ans); } } // This code is contributed by 29AjayKumar |
Javascript
<script> // Javascript program to find circumradius of // a cyclic quadrilateral using sides // Function to return the circumradius // of a cyclic quadrilateral using sides function Circumradius(a, b, c, d) { // Find semiperimeter var s = (a + b + c + d) / 2.0; // Calculate the radius var radius = Math.sqrt(((a * b) + (c * d)) * ((a * c) + (b * d)) * ((a * d) + (b * c)) / ((s - a) * (s - b) * (s - c) * (s - d))); return radius / 4; } // Driver code var A = 3; var B = 4; var C = 5; var D = 6; // Function call var ans = Circumradius(A, B, C, D); // Print the radius document.write(ans.toFixed(2)); // This code is contributed by Khushboogoyal499 </script> |
3.29
Time Complexity: O(log s)
Auxiliary Space: O(1)
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