Given a string str representing a number, the task is to find whether the number is valid or not if it made topsy-turvy i.e upside-down.
Examples:
Input: str = “1183”
Output: Yes
upside-down(1183) = 1183
Input: str = “983”
Output: No
Approach: Only the digits 1, 3 and 8 are the digits that can form another valid digit when turned upside-down. If the number contains a digit other than these then print No else print Yes.
Below is the implementation of the above approach:
C++
// C++ implementation of the approach#include <bits/stdc++.h>using namespace std;// Function that returns true if// str is Topsy Turvybool topsyTurvy(string str){ // For every character of the string for (int i = 0; i < str.length(); i++) { // If the current digit cannot form a // valid digit when turned upside-down if (str[i] == '2' || str[i] == '4' || str[i] == '5' || str[i] == '6' || str[i] == '7' || str[i] == '9') { return false; } } return true;}// Driver codeint main(){ string str = "1234"; if (topsyTurvy(str)) cout << "Yes"; else cout << "No"; return 0;} |
Java
// Java implementation of the approachimport java.util.*;class GFG {// Function that returns true if// str is Topsy Turvystatic boolean topsyTurvy(char[] str){ // For every character of the string for (int i = 0; i < str.length; i++) { // If the current digit cannot form a // valid digit when turned upside-down if (str[i] == '2' || str[i] == '4' || str[i] == '5' || str[i] == '6' || str[i] == '7' || str[i] == '9') { return false; } } return true;}// Driver codepublic static void main(String[] args) { String str = "1234"; if (topsyTurvy(str.toCharArray())) System.out.println("Yes"); else System.out.println("No");}} // This code is contributed by Rajput-Ji |
Python3
# Python3 implementation of the approach # Function that returns true if # str is Topsy Turvy def topsyTurvy(string) : # For every character of the string for i in range(len(string)) : # If the current digit cannot form a # valid digit when turned upside-down if (string[i] == '2' or string[i] == '4' or string[i] == '5' or string[i] == '6' or string[i] == '7' or string[i] == '9') : return False; return True; # Driver code if __name__ == "__main__" : string = "1234"; if (topsyTurvy(string)) : print("Yes"); else : print("No"); # This code is contributed by AnkitRai01 |
C#
// C# implementation of the approachusing System;class GFG {// Function that returns true if// str is Topsy Turvystatic bool topsyTurvy(char[] str){ // For every character of the string for (int i = 0; i < str.Length; i++) { // If the current digit cannot form a // valid digit when turned upside-down if (str[i] == '2' || str[i] == '4' || str[i] == '5' || str[i] == '6' || str[i] == '7' || str[i] == '9') { return false; } } return true;}// Driver codepublic static void Main(String[] args) { String str = "1234"; if (topsyTurvy(str.ToCharArray())) Console.WriteLine("Yes"); else Console.WriteLine("No");}}// This code is contributed by 29AjayKumar |
Javascript
<script>// Javascript implementation of the approach// Function that returns true if// str is Topsy Turvyfunction topsyTurvy( str){ // For every character of the string for (var i = 0; i < str.length; i++) { // If the current digit cannot form a // valid digit when turned upside-down if (str[i] == '2' || str[i] == '4' || str[i] == '5' || str[i] == '6' || str[i] == '7' || str[i] == '9') { return false; } } return true;}// Driver codevar str = "1234";if (topsyTurvy(str)) document.write( "Yes");else document.write( "No");</script> |
Output:
No
Time Complexity: O(|str|)
Auxiliary Space: O(1)
Feeling lost in the world of random DSA topics, wasting time without progress? It’s time for a change! Join our DSA course, where we’ll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!
