Given string str of length N, the task is to check if the given string contains only special characters or not. If the string contains only special characters, then print “Yes”. Otherwise, print “No”.
Examples:
Input: str = “@#$&%!~”
Output: Yes
Explanation:
Given string contains only special characters.
Therefore, the output is Yes.Input: str = “Geeks4Geeks@#”
Output: No
Explanation:
Given string contains alphabets, number, and special characters.
Therefore, the output is No.
Naive Approach: Iterate over the string and check if the string contains only special characters or not. Follow the steps below to solve the problem:
- Traverse the string and for each character, check if its ASCII value lies in the ranges [32, 47], [58, 64], [91, 96] or [123, 126]. If found to be true, it is a special character.
- Print Yes if all characters lie in one of the aforementioned ranges. Otherwise, print No.
Time Complexity: O(N)
Auxiliary Space: O(1)
Space-Efficient Approach: The idea is to use Regular Expression to optimize the above approach. Follow the steps below:
- Create the following regular expression to check if the given string contains only special characters or not.
regex = “[^a-zA-Z0-9]+”
where,
- [^a-zA-Z0-9] represents only special characters.
- + represents one or more times.
- Match the given string with the Regular Expression using Pattern.matcher() in Java
- Print Yes if the string matches with the given regular expression. Otherwise, print No.
Below is the implementation of the above approach:
C++
// C++ program to check if the string// contains only special characters#include <iostream>#include <regex>using namespace std;// Function to check if the string contains only special characters.void onlySpecialCharacters(string str){ // Regex to check if the string contains only special characters. const regex pattern("[^a-zA-Z0-9]+"); // If the string // is empty then print "No" if (str.empty()) { cout<< "No"; return ; } // Print "Yes" if the string contains only special characters // matched the ReGex if(regex_match(str, pattern)) { cout<< "Yes"; } else { cout<< "No"; }}// Driver Codeint main(){ // Given string str string str = "@#$&%!~"; onlySpecialCharacters(str) ; return 0;}// This code is contributed by yuvraj_chandra |
Java
// Java program to check if the string// contains only special charactersimport java.util.regex.*;class GFG { // Function to check if a string // contains only special characters public static void onlySpecialCharacters( String str) { // Regex to check if a string contains // only special characters String regex = "[^a-zA-Z0-9]+"; // Compile the ReGex Pattern p = Pattern.compile(regex); // If the string is empty // then print No if (str == null) { System.out.println("No"); return; } // Find match between given string // & regular expression Matcher m = p.matcher(str); // Print Yes If the string matches // with the Regex if (m.matches()) System.out.println("Yes"); else System.out.println("No"); } // Driver Code public static void main(String args[]) { // Given string str String str = "@#$&%!~"; // Function Call onlySpecialCharacters(str); }} |
Python3
# Python program to check if the string# contains only special charactersimport re# Function to check if a string# contains only special charactersdef onlySpecialCharacters(Str): # Regex to check if a string contains # only special characters regex = "[^a-zA-Z0-9]+" # Compile the ReGex p=re.compile(regex) # If the string is empty # then print No if(len(Str) == 0): print("No") return # Print Yes If the string matches # with the Regex if(re.search(p, Str)): print("Yes") else: print("No")# Driver Code# Given string strStr = "@#$&%!~"# Function CallonlySpecialCharacters(Str)# This code is contributed by avanitrachhadiya2155 |
C#
// C# program to check if // the string contains only // special charactersusing System;using System.Text.RegularExpressions; class GFG{// Function to check if a string// contains only special characterspublic static void onlySpecialchars(String str){ // Regex to check if a string // contains only special // characters String regex = "[^a-zA-Z0-9]+"; // Compile the ReGex Regex rgex = new Regex(regex); // If the string is empty // then print No if (str == null) { Console.WriteLine("No"); return; } // Find match between given // string & regular expression MatchCollection matchedAuthors = rgex.Matches(str); // Print Yes If the string matches // with the Regex if (matchedAuthors.Count != 0) Console.WriteLine("Yes"); else Console.WriteLine("No");}// Driver Codepublic static void Main(String []args){ // Given string str String str = "@#$&%!~"; // Function Call onlySpecialchars(str);}}// This code is contributed by Princi Singh |
Javascript
<script> // JavaScript program to check if // the string contains only // special characters // Function to check if a string // contains only special characters function onlySpecialchars(str) { // Regex to check if a string // contains only special // characters var regex = /^[^a-zA-Z0-9]+$/; // If the string is empty // then print No if (str.length < 1) { document.write("No"); return; } // Find match between given // string & regular expression var matchedAuthors = regex.test(str); // Print Yes If the string matches // with the Regex if (matchedAuthors) document.write("Yes"); else document.write("No"); } // Driver Code // Given string str var str = "@#$&%!~"; // Function Call onlySpecialchars(str); </script> |
Output:
Yes
Time Complexity: O(N)
Auxiliary Space: O(1)
Another approach: This is simple approach in which just checking the string contain any alphabets and digits or not. If contains then print No else print Yes.
1. Take the a string str and call the function Check_Special_Chars passing string as parameter.
2. The function Check_Special_Chars takes a string as input and loops over each character in the string using a for loop.
3. Now in the inner loop check each character is an alphabet (both upper and lower case) A to Z ASCII value (65 to 90) and a to z ASCII value(97 to 122) or not.
If the character is an alphabet, the function prints “No” and returns from the function.
4.The second inner for loop checks if the current character is a number (0 to 9) ASCII value(48 to 57). If the character is a number, the function prints “No” and returns from the function.
5. If the function loops through the entire string without finding any alphabets or numbers, it means that the string only contains special characters. In this case, the function prints “Yes”.
Below the implementation of above approach.
C++
// C++ program to check if the string// contains only special characters#include <bits/stdc++.h>using namespace std;// Function to check if the string contains only special characters.void Check_Special_Chars(string s){ // Looping over the string for(int i = 0; i<s.length();i++) { // checking for a-z and A-Z characters for(int k = 0; k <26; k++) { // if present then print No and return if(s[i]==k+65 || s[i]==k+97) { cout<<"No"<<endl; return; } } // Checking for 0-9 characters for(int k = 0; k<10; k++) { // if present then print No and return if(s[i]==k+48) { cout<<"No"<<endl; return; } } } // if not present a-z, A-Z and 0-9, then only special character present and print Yes cout<<"Yes"<<endl;}// Driver Codeint main(){// Given string strstring str = "@#$&%!~";Check_Special_Chars(str) ;return 0;} |
Java
import java.util.*;class Main { // Function to check if the string contains only special characters. static void Check_Special_Chars(String s) { // Looping over the string for(int i = 0; i < s.length(); i++) { // checking for a-z and A-Z characters for(int k = 0; k < 26; k++) { // if present then print No and return if(s.charAt(i) == (char)(k + 65) || s.charAt(i) == (char)(k + 97)) { System.out.println("No"); return; } } // Checking for 0-9 characters for(int k = 0; k < 10; k++) { // if present then print No and return if(s.charAt(i) == (char)(k + 48)) { System.out.println("No"); return; } } } // if not present a-z, A-Z and 0-9, then only special character present and print Yes System.out.println("Yes"); } // Driver Code public static void main(String[] args) { // Given string str String str = "@#$&%!~"; Check_Special_Chars(str); }} |
Python3
class Main: # Function to check if the string contains only special characters. @staticmethod def Check_Special_Chars(s): # Looping over the string for i in range(len(s)): # checking for a-z and A-Z characters for k in range(26): # if present then print No and return if s[i] == chr(k + 65) or s[i] == chr(k + 97): print("No") return # Checking for 0-9 characters for k in range(10): # if present then print No and return if s[i] == chr(k + 48): print("No") return # if not present a-z, A-Z and 0-9, then only special character # present and print Yes print("Yes") # Driver Code # Given string strstr = "@#$&%!~"Main.Check_Special_Chars(str) |
C#
using System;class Program { // Function to check if the string contains only special // characters. static void Check_Special_Chars(string s) { // Looping over the string for (int i = 0; i < s.Length; i++) { // checking for a-z and A-Z characters for (int k = 0; k < 26; k++) { // if present then print No and return if (s[i] == k + 65 || s[i] == k + 97) { Console.WriteLine("No"); return; } } // Checking for 0-9 characters for (int k = 0; k < 10; k++) { // if present then print No and return if (s[i] == k + 48) { Console.WriteLine("No"); return; } } } // if not present a-z, A-Z and 0-9, then only // special character present and print Yes Console.WriteLine("Yes"); } // Driver Code static void Main(string[] args) { // Given string str string str = "@#$&%!~"; Check_Special_Chars(str); }} |
Javascript
// Function to check if the string contains only special characters.function Check_Special_Chars(s) { // Looping over the string for (let i = 0; i < s.length; i++) { // checking for a-z and A-Z characters for (let k = 0; k < 26; k++) { // if present then print No and return if (s[i] == String.fromCharCode(k + 65) || s[i] == String.fromCharCode(k + 97)) { console.log("No"); return; } } // Checking for 0-9 characters for (let k = 0; k < 10; k++) { // if present then print No and return if (s[i] == String.fromCharCode(k + 48)) { console.log("No"); return; } } } // if not present a-z, A-Z and 0-9, then only special character present and print Yes console.log("Yes");}// Driver Codelet str = "@#$&%!~";Check_Special_Chars(str); |
Output
Yes
Time Complexity: O(N)
Auxiliary Space: O(1)
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