Thursday, July 4, 2024

Centrosymmetric Matrix

Given a matrix of size n x n. The task is to check whether the given matrix is a Centrosymmetric Matrix or not.
In mathematics, a centrosymmetric matrix is a matrix that is symmetric about its center.

Examples:  

Input : n = 3,
        m[][] = { { 1, 3, 5 },
                  { 6, 8, 6 },
                  { 5, 3, 1 } };
Output : Yes

Input : n = 3, 
        m[][] = { { 1, 3, 5 },
                  { 6, 8, 6 },
                  { 5, 3, 0 } };
Output : No

The idea is to check for each element whether m[i][j] is equal to m[n – i – 1][n – j – 1]. If any element does not satisfy the above condition, then print “No”, otherwise print “Yes”.

Below is the implementation of the above approach:  

C++




// CPP Program to check whether given
// matrix is centrosymmetric or not.
#include <bits/stdc++.h>
using namespace std;
#define N 3
 
bool checkCentrosymmetricted(int n, int m[N][N])
{
    int mid_row;
 
    // Finding the middle row of the matrix
    if (n & 1)
        mid_row = n / 2 + 1;
    else
        mid_row = n / 2;
 
    // for each row upto middle row.
    for (int i = 0; i < mid_row; i++) {
 
        // If each element and its corresponding
        // element is not equal then return false.
        for (int j = 0; j < n; j++) {
            if (m[i][j] != m[n - i - 1][n - j - 1])
                return false;
        }
    }
 
    return true;
}
 
// Driven Program
int main()
{
    int n = 3;
    int m[N][N] = { { 1, 3, 5 },
                    { 6, 8, 6 },
                    { 5, 3, 1 } };
 
    (checkCentrosymmetricted(n, m) ?
              (cout << "Yes") : (cout << "No"));
 
    return 0;
}


Java




// Java Program to check whether given
// matrix is centrosymmetric or not.
import java.io.*;
 
class GFG {
         
    static int N = 3;
     
    static boolean checkCentrosymmetricted(
                           int n, int m[][])
    {
        int mid_row;
     
        // Finding the middle row of the
        // matrix
        if ((n & 1)>0)
            mid_row = n / 2 + 1;
        else
            mid_row = n / 2;
     
        // for each row upto middle row.
        for (int i = 0; i < mid_row; i++)
        {
     
            // If each element and its
            // corresponding element is
            // not equal then return false.
            for (int j = 0; j < n; j++)
            {
                if (m[i][j] !=
                  m[n - i - 1][n - j - 1])
                    return false;
            }
        }
     
        return true;
    }
     
    // Driven Program
    public static void main (String[] args)
    {
        int n = 3;
        int m[][] = { { 1, 3, 5 },
                      { 6, 8, 6 },
                      { 5, 3, 1 } };
 
    if(checkCentrosymmetricted(n, m))
        System.out.println( "Yes");
    else
        System.out.println( "No");
    }
}
 
// This code is contributed by anuj_67.


Python3




# Python3 Program to check whether given
# matrix is centrosymmetric or not.
 
def checkCentrosymmetricted( n, m):
 
    mid_row = 0;
 
    # Finding the middle row
    # of the matrix
    if ((n & 1) > 0):
        mid_row = n / 2 + 1;
    else:
        mid_row = n / 2;
 
    # for each row upto middle row.
    for i in range(int(mid_row)):
 
        # If each element and
        # its corresponding
        # element is not equal
        # then return false.
        for j in range(n):
            if (m[i][j] != m[n - i - 1][n - j - 1]):
                return False;
 
    return True;
     
# Driver Code
n = 3;
m = [[1, 3, 5 ],
     [ 6, 8, 6 ],
     [ 5, 3, 1 ]];
 
if(checkCentrosymmetricted(n, m)):
    print("Yes");
else:
    print("No");
         
# This code is contributed by mits


C#




// C# Program to check whether given
// matrix is centrosymmetric or not.
using System;
 
class GFG {
         
    ///static int N = 3;
     
    static bool checkCentrosymmetricted(
                        int n, int [,]m)
    {
        int mid_row;
     
        // Finding the middle row of the
        // matrix
        if ((n & 1)>0)
            mid_row = n / 2 + 1;
        else
            mid_row = n / 2;
     
        // for each row upto middle row.
        for (int i = 0; i < mid_row; i++)
        {
     
            // If each element and its
            // corresponding element is
            // not equal then return false.
            for (int j = 0; j < n; j++)
            {
                if (m[i,j] !=
                m[n - i - 1,n - j - 1])
                    return false;
            }
        }
     
        return true;
    }
     
    // Driven Program
    public static void Main()
    {
        int n = 3;
        int [,]m = { { 1, 3, 5 },
                    { 6, 8, 6 },
                    { 5, 3, 1 } };
 
        if(checkCentrosymmetricted(n, m))
            Console.WriteLine( "Yes");
        else
            Console.WriteLine( "No");
    }
}
 
// This code is contributed by anuj_67.


PHP




<?php
// PHP Program to check whether given
// matrix is centrosymmetric or not.
 
//$N = 3;
 
function checkCentrosymmetricted( $n, $m)
{
    $mid_row;
 
    // Finding the middle row
    // of the matrix
    if ($n & 1)
        $mid_row = $n / 2 + 1;
    else
        $mid_row = $n / 2;
 
    // for each row upto middle row.
    for($i = 0; $i < $mid_row; $i++)
    {
 
        // If each element and
        // its corresponding
        // element is not equal
        // then return false.
        for($j = 0; $j < $n; $j++) {
            if ($m[$i][$j] != $m[$n - $i - 1]
                                [$n - $j - 1])
                return false;
        }
    }
 
    return true;
}
     
    // Driver Code
    $n = 3;
    $m = array(array(1, 3, 5 ),
                array( 6, 8, 6 ),
                array( 5, 3, 1 ));
 
    if(checkCentrosymmetricted($n, $m) )
        echo "Yes" ;
    else
        echo "No";
         
// This code is contributed by anuj_67.
?>


Javascript




<script>
 
 
// Javascript Program to check whether given
// matrix is centrosymmetric or not.
 
let N = 3
 
function checkCentrosymmetricted( n,  m)
{
    let mid_row;
 
    // Finding the middle row of the matrix
    if (n & 1)
        mid_row = Math.floor(n / 2) + 1;
    else
        mid_row = n / 2;
 
    // for each row upto middle row.
    for (let i = 0; i < mid_row; i++) {
 
        // If each element and its corresponding
        // element is not equal then return false.
        for (let j = 0; j < n; j++) {
            if (m[i][j] != m[n - i - 1][n - j - 1])
                return false;
        }
    }
 
    return true;
}
 
// Driver Code
 
let n = 3;
let m = [ [ 1, 3, 5 ],
        [ 6, 8, 6 ],
        [ 5, 3, 1 ] ];
 
(checkCentrosymmetricted(n, m) ?
              (document.write("Yes")) : document.write("No"));
 
// This code is contributed by jana_sayanta.
</script>


Output

Yes

Time Complexity: O(N2)
Auxiliary Space: O(1)

Feeling lost in the world of random DSA topics, wasting time without progress? It’s time for a change! Join our DSA course, where we’ll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!

Nokonwaba Nkukhwana
Experience as a skilled Java developer and proven expertise in using tools and technical developments to drive improvements throughout a entire software development life cycle. I have extensive industry and full life cycle experience in a java based environment, along with exceptional analytical, design and problem solving capabilities combined with excellent communication skills and ability to work alongside teams to define and refine new functionality. Currently working in springboot projects(microservices). Considering the fact that change is good, I am always keen to new challenges and growth to sharpen my skills.
RELATED ARTICLES

LEAVE A REPLY

Please enter your comment!
Please enter your name here

Most Popular

Recent Comments