Given a singly linked list of 0s and 1s find its decimal equivalent.
Input: 0->0->0->1->1->0->0->1->0 Output: 50 Input: 1->0->0 Output: 4
The decimal value of an empty linked list is considered as 0.
Initialize the result as 0. Traverse the linked list and for each node, multiply the result by 2 and add the node’s data to it.
C
// C Program to find decimal value // of binary linked list#include<iostream>using namespace std;// Link list Node struct Node{ bool data; struct Node* next;};/* Returns decimal value of binary linked list */int decimalValue(struct Node *head){ // Initialized result int res = 0; // Traverse linked list while (head != NULL) { // Multiply result by 2 and add // head's data res = (res << 1) + head->data; // Move next head = head->next; } return res;}// Utility function to create a // new node.Node *newNode(bool data){ struct Node *temp = new Node; temp->data = data; temp->next = NULL; return temp;}// Driver codeint main(){ // Start with the empty list struct Node* head = newNode(1); head->next = newNode(0); head->next->next = newNode(1); head->next->next->next = newNode(1); cout << "Decimal value is " << decimalValue(head); return 0;} |
Output :
Decimal value is 11
Time Complexity: O(n) where n is the number of nodes in the given linked list.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
Please refer complete article on Decimal Equivalent of Binary Linked List for more details!
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