Given an integer that represents the year, the task is to check if this is a leap year, with the help of Ternary Operator. A year is a leap year if the following conditions are satisfied:
- The year is multiple of 400.
- The year is a multiple of 4 and not a multiple of 100.
Following is pseudo-code
if year is divisible by 400 then is_leap_year else if year is divisible by 100 then not_leap_year else if year is divisible by 4 then is_leap_year else not_leap_year
Below is the implementation of the above approach:
C
// C program to check if a given // year is a leap year or not #include <stdbool.h> #include <stdio.h> bool checkYear(int n) { return (n % 400 == 0) ? true : (n % 4 == 0) ? (n % 100 != 0) : false ? true : false; } // Driver code int main() { int year = 2000; checkYear(year) ? printf("Leap Year") : printf("Not a Leap Year"); return 0; } |
Output
Leap Year
Time Complexity: O(1), As only constant time operations are performed.
Auxiliary Space: O(1), As constant extra space is used.
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