Given here is an equilateral triangle with side length a, which inscribes a circle, which in turn inscribes a square. The task is to find the area of this square.
Examples:
Input: a = 6 Output: 1 Input: a = 10 Output: 0.527046
Approach:
let r be the radius of circle,
hence it is the inradius of equilateral triangle, so r = a /(2 * ?3)
diagonal of square, d = diameter of circle = 2 * r = a/ ?3
So, area of square, A = 0.5 * d * d
hence A = (1/2) * (a^2) / (3) = (a^2/6)
Below is the implementation of the above approach:
C++
// C++ Program to find the area of the square // inscribed within the circle which in turn // is inscribed in an equilateral triangle #include <bits/stdc++.h> using namespace std; // Function to find the area of the square float area( float a) { // a cannot be negative if (a < 0) return -1; // area of the square float area = sqrt (a) / 6; return area; } // Driver code int main() { float a = 10; cout << area(a) << endl; return 0; } |
Java
// Java Program to find the area of the square // inscribed within the circle which in turn // is inscribed in an equilateral triangle import java.io.*; class GFG { // Function to find the area of the square static float area( float a) { // a cannot be negative if (a < 0 ) return - 1 ; // area of the square float area = ( float )Math.sqrt(a) / 6 ; return area; } // Driver code public static void main (String[] args) { float a = 10 ; System.out.println( area(a)); // This code is contributed // by inder_verma.. } } |
Python 3
# Python3 Program to find the area # of the square inscribed within # the circle which in turn is # inscribed in an equilateral triangle # import everything from math lib. from math import * # Function to find the area # of the square def area(a): # a cannot be negative if a < 0 : return - 1 # area of the square area = sqrt(a) / 6 return area # Driver code if __name__ = = "__main__" : a = 10 print ( round (area(a), 6 )) # This code is contributed by ANKITRAI1 |
C#
// C# Program to find the area // of the square inscribed within // the circle which in turn is // inscribed in an equilateral triangle using System; class GFG { // Function to find the area // of the square static float area( float a) { // a cannot be negative if (a < 0) return -1; // area of the square float area = ( float )Math.Sqrt(a) / 6; return area; } // Driver code public static void Main () { float a = 10; Console.WriteLine(area(a)); } } // This code is contributed // by inder_verma |
PHP
<?php // PHP Program to find the area // of the square inscribed within // the circle which in turn is // inscribed in an equilateral triangle // Function to find the // area of the square function area( $a ) { // a cannot be negative if ( $a < 0) return -1; // area of the square $area = sqrt( $a ) / 6; return $area ; } // Driver code $a = 10; echo area( $a ); // This code is contributed // by inder_verma ?> |
Javascript
<script> // javascript Program to find the area of the square // inscribed within the circle which in turn // is inscribed in an equilateral triangle // Function to find the area of the square function area(a) { // a cannot be negative if (a < 0) return -1; // area of the square var area = Math.sqrt(a) / 6; return area; } // Driver code var a = 10; document.write( area(a).toFixed(6)); // This code contributed by shikhasingrajput </script> |
0.527046
Time complexity : O(log(a)) for given side a, as complexity of inbuilt sqrt function
Auxiliary Space : O(1)
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