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Algorithms | Recursion | Question 9

Predict the output:

C




#include <stdio.h>
void crazy(int n, int a, int b)
{
    if (n <= 0)
        return;
    crazy(n - 1, a, b + n);
    printf("%d %d %d \n",n,a,b);
    crazy(n-1, b, a+n);
}
 
int main()
{
    crazy(3, 4, 5);
    return 0;
}


(A)

1 4 10
2 4 8
1 8 6
3 4 5
1 5 9
2 5 7
1 7 7

(B)

3 4 5
1 4 10
2 4 8
1 8 6
1 5 9
2 5 7
1 7 7

(C)

1 4 10
2 4 8
1 8 6
3 4 5

(D)

3 4 5
1 5 9
2 5 7
1 7 7

Answer: (A)
Explanation:

Call(3,4,5)

  • crazy(3, 4, 5) calls crazy(2, 4, 5 + 3) 
  • crazy(2, 4, 8) calls crazy(1, 4, 8 + 2) 
  • crazy(1, 4, 10) calls crazy(0, 4, 10 + 1) 
  • crazy(0, 4, 11) returns immediately as the base case is reached. and prints 1, 4, 10.
  • crazy(0, 11,4). return as the base case is reached.

Now, we wrap up the recursive calls:

  • call crazy(2,4,8) prints 2,4,8 and again call for crazy(1,8, 6). which will print 1,8,6.
  • call crazy(3,4,5) prints 3,4,5 and again call for crazy(2,5, 7). which will again call for (1,5,9) prints 1 5 9.
  • call crazy (2,5,7) prints 2,5,7 and again call for crazy(1,7,7), which will print 1,7,7.

Hence (A) is the correct Option.
 

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