Many operations such as grouping and conversions are possible using Python dictionaries. But sometimes, we can also have a problem in which we need to perform the aggregation of values of key in dictionary list. This task is common in day-day programming. Let’s discuss certain ways in which this task can be performed.
Method #1: Using sum() + list comprehension This is the one-liner approach to perform the task of getting the sum of particular key while iterating to the similar keys in list of dictionaries using list comprehension.
Python3
# Python3 code to demonstrate working of# Value summation of key in dictionary# Using sum() + list comprehension# Initialize listtest_list = [{'gfg' : 1, 'is' : 2, 'best' : 3}, {'gfg' : 7, 'is' : 3, 'best' : 5}, {'gfg' : 9, 'is' : 8, 'best' : 6}] # printing original listprint("The original list is : " + str(test_list))# Value summation of key in dictionary# Using sum() + list comprehensionres = sum(sub['gfg'] for sub in test_list)# printing resultprint("The sum of particular key is : " + str(res)) |
The original list is : [{‘best’: 3, ‘gfg’: 1, ‘is’: 2}, {‘best’: 5, ‘gfg’: 7, ‘is’: 3}, {‘best’: 6, ‘gfg’: 9, ‘is’: 8}] The sum of particular key is : 17
Time Complexity: O(n*n) where n is the number of elements in the list “test_list”.
Auxiliary Space: O(n), where n is the number of elements in the new res list
Method #2: Using sum() + itemgetter() + map() The combination of these functions can also be used to perform this task. In this, the main difference is that the comprehension task is done by map() and the key access task is done by the itemgetter().
Python3
# Python3 code to demonstrate working of# Value summation of key in dictionary# Using sum() + itemgetter() + map()import operator# Initialize listtest_list = [{'gfg' : 1, 'is' : 2, 'best' : 3}, {'gfg' : 7, 'is' : 3, 'best' : 5}, {'gfg' : 9, 'is' : 8, 'best' : 6}] # printing original listprint("The original list is : " + str(test_list))# Value summation of key in dictionary# Using sum() + itemgetter() + map()res = sum(map(operator.itemgetter('gfg'), test_list))# printing resultprint("The sum of particular key is : " + str(res)) |
The original list is : [{‘best’: 3, ‘gfg’: 1, ‘is’: 2}, {‘best’: 5, ‘gfg’: 7, ‘is’: 3}, {‘best’: 6, ‘gfg’: 9, ‘is’: 8}] The sum of particular key is : 17
Time Complexity: O(n) where n is the number of elements in the test_list. The sum() + itemgetter() + map() is used to perform the task and it takes O(n) time.
Auxiliary Space: O(1) constant additional space is required.
Method #3: Using reduce() + lambda function
This is another way to perform the summation of key values in a list of dictionaries. In this method, we use the reduce() function to iterate through the list of dictionaries and the lambda function to perform the summation of specific key values.
Python3
# Python3 code to demonstrate working of# Value summation of key in dictionary# Using reduce() + lambda functionfrom functools import reduce # Initialize listtest_list = [{'gfg' : 1, 'is' : 2, 'best' : 3}, {'gfg' : 7, 'is' : 3, 'best' : 5}, {'gfg' : 9, 'is' : 8, 'best' : 6}] # printing original listprint("The original list is : " + str(test_list)) # Value summation of key in dictionary# Using reduce() + lambda functionres = reduce(lambda x, y: x + y['gfg'], test_list, 0) # printing resultprint("The sum of particular key is : " + str(res))#This code is contributed by Edula Vinay Kumar Reddy |
The original list is : [{'gfg': 1, 'is': 2, 'best': 3}, {'gfg': 7, 'is': 3, 'best': 5}, {'gfg': 9, 'is': 8, 'best': 6}]
The sum of particular key is : 17
Time complexity: O(n)
Auxiliary Space: O(1)
Method #4: Using a for loop
Use a for loop to iterate over the list of dictionaries and add up the values of the key ‘gfg‘.
Python3
# Python3 code to demonstrate working of# Value summation of key in dictionary# Using for loop# Initialize listtest_list = [{'gfg' : 1, 'is' : 2, 'best' : 3}, {'gfg' : 7, 'is' : 3, 'best' : 5}, {'gfg' : 9, 'is' : 8, 'best' : 6}] # printing original listprint("The original list is : " + str(test_list))# Value summation of key in dictionary# Using for loopres = 0for d in test_list: res += d['gfg']# printing resultprint("The sum of particular key is : " + str(res)) |
The original list is : [{'gfg': 1, 'is': 2, 'best': 3}, {'gfg': 7, 'is': 3, 'best': 5}, {'gfg': 9, 'is': 8, 'best': 6}]
The sum of particular key is : 17
Time complexity: O(n), where n is the length of the list. This is because we are iterating over each dictionary in the list once, and accessing a single key from each dictionary.
Auxiliary space: O(1), since we are only using a single variable to keep track of the sum and not using any extra data structures.
Method 5: Using Generator Expression and sum()
STEP:
- Create a generator expression that yields the value of key ‘gfg’ from each dictionary in test_list.
- Use sum() function to calculate the sum of all the values yielded by the generator expression.
- Print the final result.
Python3
# Python3 code to demonstrate working of# Value summation of key in dictionary# Using Generator Expression and sum()# Initialize listtest_list = [{'gfg' : 1, 'is' : 2, 'best' : 3}, {'gfg' : 7, 'is' : 3, 'best' : 5}, {'gfg' : 9, 'is' : 8, 'best' : 6}] # printing original listprint("The original list is : " + str(test_list))# Value summation of key in dictionary# Using Generator Expression and sum()res = sum(d['gfg'] for d in test_list)# printing resultprint("The sum of particular key is : " + str(res)) |
The original list is : [{'gfg': 1, 'is': 2, 'best': 3}, {'gfg': 7, 'is': 3, 'best': 5}, {'gfg': 9, 'is': 8, 'best': 6}]
The sum of particular key is : 17
Time complexity: O(n)
Auxiliary space: O(1)
