Sometimes, we need to find the specific problem of getting the pair that yields the minimum product, this can be solved by sorting and getting the first and second elements of the list. But in some case, we don’t with to change the ordering of list and perform some operation in the similar list without using extra space. Let’s discuss certain ways in which this can be performed.
Note: All elements in the list are positive integer.
Method #1 : Using list comprehension + min() + combination() + lambda This particular task can be performed using the combination of above functions in which we use list comprehension to bind all the functionalities and min function to get the minimum product, combination function finds all product internally and lambda function is used to compute the product.
Python3
# Python3 code to demonstrate # Minimum Product Pair in List # using list comprehension + min() + combinations() + lambda from itertools import combinations # initializing list test_list = [ 3 , 4 , 1 , 7 , 9 , 1 ] # printing original list print ("The original list : " + str (test_list)) # using list comprehension + min() + combinations() + lambda # Minimum Product Pair in List res = min (combinations(test_list, 2 ), key = lambda sub: sub[ 0 ] * sub[ 1 ]) # print result print ("The minimum product pair is : " + str (res)) |
The original list : [3, 4, 1, 7, 9, 1] The minimum product pair is : (1, 1)
Time Complexity: O(n*n), where n is the number of elements in the list “test_list”.
Auxiliary Space: O(n), where n is the number of elements in the list “test_list”.
Method #2 : Using list comprehension + nsmallest() + combination() + lambda This method has potential of not only finding a single minimum but also k minimum product pairs if required and uses nsmallest function instead of min function to achieve this functionality.
Python3
# Python3 code to demonstrate # Minimum Product Pair in List # using list comprehension + nsmallest() + combinations() + lambda from itertools import combinations from heapq import nsmallest # initializing list test_list = [ 3 , 4 , 1 , 7 , 9 , 8 ] # printing original list print ("The original list : " + str (test_list)) # using list comprehension + nsmallest() + combinations() + lambda # Minimum Product Pair in List res = nsmallest( 2 , combinations(test_list, 2 ), key = lambda sub: sub[ 0 ] * sub[ 1 ]) # print result print ("The minimum product pair is : " + str (res)) |
The original list : [3, 4, 1, 7, 9, 8] The minimum product pair is : [(3, 1), (4, 1)]
Time Complexity: O(n*n), where n is the number of elements in the list “test_list”.
Auxiliary Space: O(n), where n is the number of elements in the list “test_list”.