Given a 2D binary matrix of N rows and M columns. The task is to check whether the matrix is horizontal symmetric, vertical symmetric, or both. The matrix is said to be horizontal symmetric if the first row is the same as the last row, the second row is the same as the second last row, and so on. And the matrix is said to be vertical symmetric if the first column is the same as the last column, the second column is the same as the second last column, and so on. Print “VERTICAL” if the matrix is vertically symmetric, “HORIZONTAL” if the matrix is vertically symmetric, “BOTH” if the matrix is vertical and horizontal symmetric, and “NO” if not symmetric.
Examples:
Input: N = 3 M = 3 0 1 0 0 0 0 0 1 0 Output: Both First and third row are same and also second row is in middle. So Horizontal Symmetric. Similarly, First and third column are same and also second column is in middle, so Vertical Symmetric. Input: 0 0 1 1 1 0 0 0 1. Output: Both
The idea is to use pointers indicating two rows (or columns) and compare each cell of both the pointed rows (or columns).
For Horizontal Symmetry, initialize one pointer i = 0 and another pointer j = N – 1.
Now, compare each element of i-th row and j-th row. Increase i by 1 and decrease j by 1 in each loop cycle. If at least one, not an identical element, is found, mark the matrix as not horizontal symmetric.
Similarly, for Vertical Symmetry, initialize one pointer i = 0 and another pointer j = M – 1.
Now, compare each element of i-th column and j-th column. Increase i by 1 and decrease j by 1 in each loop cycle. If at least one, not an identical element, is found, mark the matrix as not vertical symmetric.
Below is the implementation of the above idea:
Python3
# Python3 program to find if a matrix is symmetric.MAX = 1000def checkHV(arr, N, M): # Initializing as both horizontal and vertical # symmetric. horizontal = True vertical = True # Checking for Horizontal Symmetry. We compare # first row with last row, second row with second # last row and so on. i = 0 k = N - 1 while(i < N // 2): # Checking each cell of a column. for j in range(M): # check if every cell is identical if (arr[i][j] != arr[k][j]): horizontal = False break i += 1 k -= 1 # Checking for Vertical Symmetry. We compare # first column with last column, second column # with second last column and so on. i = 0 k = M - 1 while(i < M // 2): # Checking each cell of a row. for j in range(N): # check if every cell is identical if (arr[i][j] != arr[k][j]): vertical = False break i += 1 k -= 1 if (not horizontal and not vertical): print("NO") elif (horizontal and not vertical): print("HORIZONTAL") elif (vertical and not horizontal): print("VERTICAL") else: print("BOTH") # Driver codemat = [[1, 0, 1],[ 0, 0, 0],[1, 0, 1]]checkHV(mat, 3, 3)# This code is contributed by shubhamsingh10 |
BOTH
Time Complexity: O(N*M).
Auxiliary Space: O(1)
Please refer complete article on Check horizontal and vertical symmetry in binary matrix for more details!
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