Given a character mesh, containing missing characters, match the string which matches the mesh.
Example:
Input : test_list = [“neveropen”, “best”, “peeks”], mesh = “_ee_s”
Output : [‘neveropen’, ‘peeks’]
Explanation : Elements according to mesh areneveropen and peeks.Input : test_list = [“neveropen”, “best”, “test”], mesh = “_e_t”
Output : [‘best’, ‘test’]
Explanation : Elements according to mesh are best and test.
Method #1: Using loop + all() + len() + zip()
The combination of the above can be used to solve this problem. In this, we perform the task of matching mesh and each string using zip() and all() is used to check for all strings, len() is used to test for correct string length matching mesh.
Python3
# Python3 code to demonstrate working of # Extract Mesh matching Strings# Using len() + loop + zip() + all()# initializing listtest_list = ["neveropen", "best", "peeks", "for", "seeks"]# printing original listprint("The original list : " + str(test_list))# initializing mesh mesh = "_ee_s"res = []for sub in test_list: # testing for matching mesh, checking each character and length if (len(sub) == len(mesh)) and all((ele1 == "_") or (ele1 == ele2) for ele1, ele2 in zip(mesh, sub)): res.append(sub)# printing result print("The extracted strings : " + str(res)) |
The original list : ['neveropen', 'best', 'peeks', 'for', 'seeks'] The extracted strings : ['neveropen', 'peeks', 'seeks']
Time Complexity: O(n)
Auxiliary Space: O(n)
Method #2: Using list comprehension
This solves the problem in a similar way as the above method, the only difference here is that 1 liner solution is provided.
Python3
# Python3 code to demonstrate working of # Extract Mesh matching Strings# Using list comprehension# initializing listtest_list = ["neveropen", "best", "peeks", "for", "seeks"]# printing original listprint("The original list : " + str(test_list))# initializing mesh mesh = "_ee_s"# one liner to solve this problemres = [sub for sub in test_list if (len(sub) == len(mesh)) and all((ele1 == "_") or (ele1 == ele2) for ele1, ele2 in zip(mesh, sub))]# printing result print("The extracted strings : " + str(res)) |
The original list : ['neveropen', 'best', 'peeks', 'for', 'seeks'] The extracted strings : ['neveropen', 'peeks', 'seeks']
Time Complexity: O(n)
Auxiliary Space: O(n)
Method 3: Using the filter() function along with lambda function
- Start by initializing the list of strings test_list and the mesh string mesh.
- Create an empty list result to store the strings that match the mesh.
- Loop through each string s in test_list.
- Check if the length of s is equal to the length of mesh. If not, move on to the next string.
- Loop through each character c in s and its corresponding character m in mesh.
- If m is equal to “_”, move on to the next character. Otherwise, check if c is equal to m. If not, move on to the next string.
- If the loop completes without finding any mismatches, append the string s to the result list.
- Once all strings have been checked, return the result list containing the matching strings.
Python3
# Python3 code to demonstrate working of # Extract Mesh matching Strings# Using filter() + lambda function# initializing listtest_list = ["neveropen", "best", "peeks", "for", "seeks"]# printing original listprint("The original list : " + str(test_list))# initializing mesh mesh = "_ee_s"# filtering the list using filter() and lambda functionres = list(filter(lambda x: len(x) == len(mesh) and all((ele1 == "_") or (ele1 == ele2) for ele1, ele2 in zip(mesh, x)), test_list))# printing result print("The extracted strings : " + str(res)) |
The original list : ['neveropen', 'best', 'peeks', 'for', 'seeks'] The extracted strings : ['neveropen', 'peeks', 'seeks']
Time Complexity: O(n*m), where n is the number of strings in the input list, and m is the length of the mesh.
Auxiliary Space: O(k), where k is the number of strings that match the mesh.
Method #4: Using a for loop and a helper function
Python3
def match_mesh(mesh, string): """ Helper function to check if a given string matches with the mesh. """ if len(mesh) != len(string): return False for i in range(len(mesh)): if mesh[i] != '_' and mesh[i] != string[i]: return False return True# initializing listtest_list = ["neveropen", "best", "peeks", "for", "seeks"]# printing original listprint("The original list : " + str(test_list))# initializing mesh mesh = "_ee_s"# extracting strings matching the mesh using for loop and helper functionres = []for string in test_list: if match_mesh(mesh, string): res.append(string)# printing result print("The extracted strings : " + str(res)) |
The original list : ['neveropen', 'best', 'peeks', 'for', 'seeks'] The extracted strings : ['neveropen', 'peeks', 'seeks']
Time complexity: O(n * m), where n is the number of strings in the list and m is the length of the mesh.
Auxiliary space: O(k), where k is the number of strings that match the mesh.
