Sometimes, while working with Python records, we can have a problem in which we need to perform cross multiplication of list of tuples. This kind of application is popular in web development domain. Let’s discuss certain ways in which this task can be performed.
Method #1 : Using list comprehension + zip() The combination of the above functionalities can be used to perform this particular task. In this, we iterate through the list using list comprehension and the multiplication across lists is performed with the help of zip().
Python3
# Python3 code to demonstrate working of# Tuple list cross multiplication# using list comprehension + zip()# initialize liststest_list1 = [(2, 4), (6, 7), (5, 1)]test_list2 = [(5, 4), (8, 10), (8, 14)]# printing original listsprint("The original list 1 : " + str(test_list1))print("The original list 2 : " + str(test_list2))# Tuple list cross multiplication# using list comprehension + zip()res = [(x[0] * y[0], x[1] * y[1]) for x, y in zip(test_list1, test_list2)]# printing resultprint("The multiplication across lists is : " + str(res)) |
The original list 1 : [(2, 4), (6, 7), (5, 1)] The original list 2 : [(5, 4), (8, 10), (8, 14)] The multiplication across lists is : [(10, 16), (48, 70), (40, 14)]
Time complexity: O(n), where n is the length of the lists test_list1 and test_list2.
Auxiliary space: O(n), where n is the length of the lists test_list1 and test_list2, since the result is stored in a new list.
Method #2 : Using loop + zip() + map() This is yet another way to perform this task. This is similar to above method, the difference is that multiplication is performed by explicit function and extending logic to each element is done by map().
Python3
# Python3 code to demonstrate working of# Tuple list cross multiplication# using max() + zip() + loop# getting Productdef prod(val) : res = 1 for ele in val: res *= ele return res # initialize liststest_list1 = [(2, 4), (6, 7), (5, 1)]test_list2 = [(5, 4), (8, 10), (8, 14)]# printing original listsprint("The original list 1 : " + str(test_list1))print("The original list 2 : " + str(test_list2))# Tuple list cross multiplication# using max() + zip() + loopres = [tuple(map(prod, zip(a, b))) for a, b in zip(test_list1, test_list2)]# printing resultprint("The multiplication across lists is : " + str(res)) |
The original list 1 : [(2, 4), (6, 7), (5, 1)] The original list 2 : [(5, 4), (8, 10), (8, 14)] The multiplication across lists is : [(10, 16), (48, 70), (40, 14)]
The time complexity of this code is O(nm), where n is the length of test_list1 and m is the length of test_list2.
The space complexity of this code is O(n), where n is the length of test_list1.
Method #3 : Using itertools.starmap()
The itertools module of Python provides us a starmap() function which is used to apply a given function to each of the tuple of an iterable. This can be used to perform this task.
Python3
# Python3 code to demonstrate working of# Tuple list cross multiplication# using itertools.starmap() # importing itertools for starmap()import itertools # initialize liststest_list1 = [(2, 4), (6, 7), (5, 1)]test_list2 = [(5, 4), (8, 10), (8, 14)] # printing original listsprint("The original list 1 : " + str(test_list1))print("The original list 2 : " + str(test_list2)) # Tuple list cross multiplication# using itertools.starmap()res = list(itertools.starmap(lambda x,y : (x[0] * y[0], x[1] * y[1]), zip(test_list1, test_list2))) # printing resultprint("The multiplication across lists is : " + str(res))#This code is contributed by Edula Vinay Kumar Reddy |
The original list 1 : [(2, 4), (6, 7), (5, 1)] The original list 2 : [(5, 4), (8, 10), (8, 14)] The multiplication across lists is : [(10, 16), (48, 70), (40, 14)]
Time Complexity: O(n)
Space Complexity: O(n)
Method#4: using max() + zip() + recursion.
Python
# Python3 code to demonstrate working of# Tuple list cross multiplication# using max() + zip() + recursion# getting Productdef prod(val) : if len(val) == 1: return val[0] return val[0] * prod(val[1:])# initialize liststest_list1 = [(2, 4), (6, 7), (5, 1)]test_list2 = [(5, 4), (8, 10), (8, 14)]# printing original listsprint("The original list 1 : " + str(test_list1))print("The original list 2 : " + str(test_list2))# Tuple list cross multiplication# using max() + zip() + recursionres = [tuple(map(prod, zip(a, b))) for a, b in zip(test_list1, test_list2)]# printing resultprint("The multiplication across lists is : " + str(res))#this code contributed by tvsk |
The original list 1 : [(2, 4), (6, 7), (5, 1)] The original list 2 : [(5, 4), (8, 10), (8, 14)] The multiplication across lists is : [(10, 16), (48, 70), (40, 14)]
Time Complexity: O(n)
Auxiliary Space: O(n)
Method #6: Using NumPy (without transposing)
Here’s another approach using NumPy, but without transposing the result. Instead, we can directly reshape the result array to get the desired output format.
Steps:
- Import the numpy library.
- Convert the given lists to numpy arrays using np.array().
- Use np.multiply() function to perform element-wise multiplication of arrays.
- Use np.reshape() function to reshape the result array to the desired format.
Python3
import numpy as np# initialize liststest_list1 = [(2, 4), (6, 7), (5, 1)]test_list2 = [(5, 4), (8, 10), (8, 14)]# convert lists to numpy arraysarr1 = np.array(test_list1)arr2 = np.array(test_list2)# perform element-wise multiplicationres_arr = np.multiply(arr1, arr2)# reshape the result array to tuple list formatres = res_arr.reshape(-1, 2).tolist()# printing resultprint("The multiplication across lists is : " + str(res)) |
OUTPUT: The multiplication across lists is : [[10, 16], [48, 70], [40, 14]]
Time Complexity: O(n)
Auxiliary Space: O(n)
