Given two sorted arrays of distinct elements, we need to print those elements from both arrays that are not common. The output should be printed in sorted order.
Examples :
Input : arr1[] = {10, 20, 30}
arr2[] = {20, 25, 30, 40, 50}
Output : 10 25 40 50
We do not print 20 and 30 as these
elements are present in both arrays.
Input : arr1[] = {10, 20, 30}
arr2[] = {40, 50}
Output : 10 20 30 40 50
Method 1:
The idea is based on the merge process of merge sort. We traverse both arrays and skip common elements.
Python3
# Python 3 program to find uncommon# elements of two sorted arraysdef printUncommon(arr1, arr2, n1, n2): i = 0 j = 0 k = 0 while (i < n1 and j < n2): # If not common, print smaller if (arr1[i] < arr2[j]): print(arr1[i], end=" ") i = i + 1 k = k + 1 elif (arr2[j] < arr1[i]): print(arr2[j], end=" ") k = k + 1 j = j + 1 # Skip common element else: i = i + 1 j = j + 1 # printing remaining elements while (i < n1): print(arr1[i], end=" ") i = i + 1 k = k + 1 while (j < n2): print(arr2[j], end=" ") j = j + 1 k = k + 1# Driver codearr1 = [10, 20, 30]arr2 = [20, 25, 30, 40, 50]n1 = len(arr1)n2 = len(arr2)printUncommon(arr1, arr2, n1, n2) |
Output
10 25 40 50
Time Complexity: O(n1 + n2), where n1 and n2 represents the size of the given two arrays.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
Method 2: Using Counter() function
Python3
from collections import Counter# Python 3 program to find uncommon# elements of two sorted arraysdef printUncommon(arr1, arr2): frequency_arr1 = Counter(arr1) frequency_arr2 = Counter(arr2) result = [] for key in frequency_arr1: if key not in frequency_arr2: result.append(key) for key in frequency_arr2: if key not in frequency_arr1: result.append(key) # Sorting the result result.sort() for i in result: print(i, end=' ')# Driver codearr1 = [10, 20, 30]arr2 = [20, 25, 30, 40, 50]printUncommon(arr1, arr2) |
Output
10 25 40 50
Please refer complete article on Print uncommon elements from two sorted arrays for more details!
Time Complexity: O(n*logn), as sort() function is used.
Auxiliary Space : O(n), where n is length of result list.
Method 3: using operator.countOf() method
Python3
# Python 3 program to find uncommon# elements of two sorted arraysimport operator as opdef printUncommon(arr1, arr2): result = [] for key in arr1: if op.countOf(arr2, key) == 0: result.append(key) for key in arr2: if op.countOf(arr1, key) == 0: result.append(key) # Sorting the result result.sort() for i in result: print(i, end=' ')# Driver codearr1 = [10, 20, 30]arr2 = [20, 25, 30, 40, 50]printUncommon(arr1, arr2) |
Output
10 25 40 50
Time Complexity: O(NLogN)
Auxiliary Space : O(N)
Feeling lost in the world of random DSA topics, wasting time without progress? It’s time for a change! Join our DSA course, where we’ll guide you on an exciting journey to master DSA efficiently and on schedule.
You’ll access excellent video content by our CEO, Sandeep Jain, tackle common interview questions, and engage in real-time coding contests covering various DSA topics. We’re here to prepare you thoroughly for online assessments and interviews.
Ready to dive in? Explore our free demo content and join our DSA course, trusted by over 100,000neveropen! Whether it’s DSA in C++, Java, Python, or JavaScript we’ve got you covered. Let’s embark on this exciting journey together!
You’ll access excellent video content by our CEO, Sandeep Jain, tackle common interview questions, and engage in real-time coding contests covering various DSA topics. We’re here to prepare you thoroughly for online assessments and interviews.
Ready to dive in? Explore our free demo content and join our DSA course, trusted by over 100,000neveropen! Whether it’s DSA in C++, Java, Python, or JavaScript we’ve got you covered. Let’s embark on this exciting journey together!
