Alice and Bob made a list of topics and both of them voted if they like or dislike the topic. They wrote 0 to denote dislike and 1 to denote like. The task is to count the number of topics that both of them like or dislike. Examples:
Input: alice = “010101” bob = “101101” Output: 3 alice and bob both like 4th and 6th topics and dislike the 5th topic. Hence, the output is 3. Input: alice = “111111” bob = “000000” Output: 0 There are no common likes or dislikes between alice and bob. Hence, the output is 0.
Input: alice = “110000” bob = “110011” Output: 4 alice and bob both like 1st and 2nd topics and dislike 3rd and 4th topics. Hence, the result is 4.
Approach:
- First, we have to iterate through each character of the string consisting of the likes and dislikes of alice.
- Then, we have to compare it with the corresponding entry of the string consisting of the likes and dislikes of bob.
- Finally, we will count the number of similar entries and print.
Below is the implementation.
Python3
# function to obtain no # of topics both alice and # bob like def commontopics(alice, bob): # initiate count with 0 count = 0 # iterating through alice for i in range(0,len(alice)): # comparing with corresponding # bob entry if alice[i] == bob[i]: # counting similar entries count += 1 # printing the count print(count) #main function def main(): commontopics("010101", "101101") commontopics("111111", "000000") commontopics("110000", "110011") # driver code if __name__ == "__main__": main() # This code is contributed by SrujayReddy |
Output:
3 0 4
The Time and Space Complexity for all the methods are the same:
Time Complexity: O(n)
Space Complexity: O(n)
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