Given the travel cost of a cab is m rupees for first n hours per hour and then is x rupees per hour, given the total time of travel in a minute the task is to find the total cost.
Note: If an hour starts then the traveler has to give the full cost for that hour.
Examples:Â
Input:Â m = 50, n = 5, x = 67, mins 2927
Output: 3198
m = 50, n = 5, x = 67, Minutes travelled = 2927, hours travelled = 49, cost = 5 * 50 + (49-5) * 67 = 2927
Input: m = 50, n = 40, x = 3, mins = 35
Output: 50
Approach: First calculate the hours traveled by taking the ceiling of (minutes traveled)/60 as if we start an hour we have to pay the price of a full hour. Then we see that our hours calculated is less than equal to n or not if it is then we directly give the answer as m*hours traveled else answer is n * m + (hours_calculated – n) * x.
Below is the implementation of the above approach:Â
C++
// CPP implementation of the above approach#include <bits/stdc++.h>using namespace std;Â
int main(){Â
    float m=50, n=5, x=67, h=2927;Â
    // calculating hours travelled    int z = (ceil(h / 60*1.0));    if(z <= n)        cout<<z * m;    else        cout<<n * m+(z-n)*x;Â
    return 0;}Â
// This code is contributed by Sanjit_Prasad |
Java
// Java implementation of the above approachÂ
import java.io.*;Â
class GFG {Â Â Â Â Â Â
    public static void main (String[] args) {            float m=50, n=5, x=67, h=2927;Â
    // calculating hours travelled    int z = (int)(Math.ceil(h / 60*1.0));    if(z <= n)        System.out.println(z * m);    else        System.out.println(n * m+(z-n)*x);    }}Â
// This code is contributed by shs |
Python3
# Python3 implementation of the above approachÂ
import math as mam, n, x, h = 50, 5, 67, 2927Â
# calculating hours travelledz = int(ma.ceil(h / 60)) if(z <= n):Â Â Â Â print(z * m)else:Â Â Â Â print(n * m+(z-n)*x) |
C#
// C# implementation of the above approachÂ
using System;Â
class GFG {Â Â Â Â Â Â
    public static void Main () {            float m=50, n=5, x=67, h=2927;Â
    // calculating hours travelled    int z = (int)(Math.Ceiling((h / 60*1.0)));    if(z <= n)      Console.WriteLine(z * m);    else        Console.WriteLine(n * m+(z-n)*x);    }}Â
// This code is contributed by anuj_67.. |
PHP
<?php// PHP implementation of the // above approach$m = 50;$n = 5;$x = 67;$h = 2927;Â
# calculating hours travelled$z = (int)(ceil($h / 60)); if($z <= $n)    print($z * $m);else    print($n * $m + ($z - $n) * $x);Â
// This code is contributed by mits?> |
Javascript
<script>Â Â // JavaScript implementation of the above approachvar m=50, n=5, x=67, h=2927;Â
// calculating hours travelledvar z = (Math.ceil(h / 60*1.0));if(z <= n)    document.write( z * m);else    document.write( n * m+(z-n)*x);Â
</script> |
3198
Time Complexity: O(1)
Auxiliary Space: O(1)
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