Consider the following functions
- f(n) = 3n^{\sqrt{n}}
- g(n) = 2^{\sqrt{n}{\log_{2}n}}
- h(n) = n!
Which of the following is true? (GATE CS 2000)
(A) h(n) is 0(f(n))
(B) h(n) is 0(g(n))
(C) g(n) is not 0(f(n))
(D) f(n) is 0(g(n))
(A)
A
(B)
B
(C)
C
(D)
D
Answer: (D)
Explanation:
g(n) = 2^
= n^f(n) and g(n) are of same asymptotic order and following statements are true. f(n) = O(g(n)) g(n) = O(f(n)). (a) and (b) are false because n! is of asymptotically higher order than n^.
Quiz of this Question
Please comment below if you find anything wrong in the above post
Whether you’re preparing for your first job interview or aiming to upskill in this ever-evolving tech landscape, neveropen Courses are your key to success. We provide top-quality content at affordable prices, all geared towards accelerating your growth in a time-bound manner. Join the millions we’ve already empowered, and we’re here to do the same for you. Don’t miss out – check it out now!
