Given an array of pairs containing length and breadth of rectangles. The task is to find the maximum area of the rectangle. Examples:
Input: (1, 2), (3, 5), (1, 1), (4, 2) Output: 15 Input: (3, 5), (5, 5), (9, 10) Output: 90
Approach:
- Use user defined Pair class to store Breadth and Height of rectangles.
- Make an array of this class.
- Now, traverse the array and find the area each time. Also, keep track of maximum area.
- Return the maximum area of rectangle.
Java
// Java code to find maximum Area import java.io.*; import java.util.*; Â
// Pair class class Rectangle { Â
    // length and     int length;     int breadth; Â
    // Rectangle Constructor     public Rectangle(int x, int y)     {         this.length = x;         this.breadth = y;     } } Â
// Class Area to calculate Area of rectangles class Area { Â
    // Function to calculate area     static int calculate_Area(Rectangle arr[])     { Â
        int max_Area = Integer.MIN_VALUE; Â
        // loop to iterate through all rectangles         // and keep track of max area         for (int i = 0; i < arr.length; i++) {             int temp_area = arr[i].length * arr[i].breadth;             if (temp_area > max_Area) {                 max_Area = temp_area;             }         }         return max_Area;     } } Â
// Driver class with main function class GFG { Â
    // Driver code     public static void main(String[] args)     {         Scanner sc = new Scanner(System.in); Â
        // Creating an array of Pair         Rectangle arr[] = new Rectangle[3]; Â
        int x = 10, y = 20;         arr[0] = new Rectangle(x, y); Â
        x = 5;         y = 25;         arr[1] = new Rectangle(x, y); Â
        x = 15;         y = 10;         arr[1] = new Rectangle(x, y); Â
        x = 12;         y = 12;         arr[2] = new Rectangle(x, y); Â
        Area obj = new Area();         System.out.println(obj.calculate_Area(arr));     } } |
Output:
200
Time complexity: O(n)
Auxiliary Space: O(1)
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