Numeric incrementing triangle pattern:
Write a program to print a Numeric incrementing triangle pattern starting with a given number N.
Examples:
Input : 3
Output : 3
4 5
6 7 8
4 5
3
Below is the implementation:
C++
#include <iostream> using namespace std; int main() { int i, j, r, N, count; N = 3; // initializing N N--; r = 5; for (i = 0; i < r; i++) { if (i <= r / 2) { count = N + 1; for (j = 0; j <= i; j++) { N++; cout << N << " "; } cout << endl; } else { N = count - (r - i); count = N; for (j = i; j < r; j++) { cout << N << " "; N++; } cout << endl; } } } |
Java
// Java Program for incrementing // or decrementing triangle pattern import java.io.*; class GFG { public static void main(String args[]) { int i, j, r, N, count = 0; N = 3; // initializing N N--; r = 5; for (i = 0; i < r; i++) { if (i <= r / 2) { count = N + 1; for (j = 0; j <= i; j++) { N++; System.out.print(N + " "); } System.out.println(); } else { N = count - (r - i); count = N; for (j = i; j < r; j++) { System.out.print(N + " "); N++; } System.out.println(); } } } } // This code is contributed // by Subhadeep Gupta |
Python 3
# python 3 program to print incrementing # and decrementing triangle pattern if __name__ == "__main__": N = 3 # initializing N N -= 1 r = 5 for i in range( r): if i <= r // 2: count = N + 1 for j in range(i + 1): N += 1 print(str(N), end = " ") print() else : N = count - (r - i) count = N for j in range(i, r): print(str(N), end = " ") N += 1 print() # This code is contributed # by ChitraNayal |
C#
// C# Program for incrementing // or decrementing triangle pattern using System; class GFG { public static void Main() { int i, j, r, N, count = 0; N = 3; // initializing N N--; r = 5; for (i = 0; i < r; i++) { if (i <= r / 2) { count = N + 1; for (j = 0; j <= i; j++) { N++; Console.Write(N + " "); } Console.Write("\n"); } else { N = count - (r - i); count = N; for (j = i; j < r; j++) { Console.Write(N + " "); N++; } Console.Write("\n"); } } } } // This code is contributed // by ChitraNayal |
PHP
<?php // PHP program for incrementing // or decrementing triangle pattern $N = 3; // initializing N $N--; $r = 5; for ($i = 0; $i < $r; $i++) { if ($i <= $r / 2) { $count = $N + 1; for ($j = 0; $j <= $i; $j++) { $N++; echo $N . " "; } echo "\n"; } else{ $N = $count - ($r - $i); $count = $N; for ($j = $i; $j < $r; $j++) { echo $N . " "; $N++; } echo "\n"; } } // This code is contributed // by ChitraNayal ?> |
Javascript
<script> var i, j, r, N, count; N = 3; // initializing N N--; r = 5; for (i = 0; i < r; i++) { if (i <= r / 2) { count = N + 1; for (j = 0; j <= i; j++) { N++; document.write(N + " "); } document.write("<br>"); } else { N = count - (r - i); count = N; for (j = i; j < r; j++) { document.write(N + " "); N++; } document.write("<br>"); } } </script> |
Output
3 4 5 6 7 8 4 5 3
Time Complexity: O(r2)
Auxiliary Space: O(1)
Numeric decrementing triangle pattern:
Write a program to print a Numeric decrementing triangle pattern starting with a given number N.
Examples:
Input : 3
Output : 3
5 4
8 7 6
5 4
3
Below is the implementation:
C++
#include <iostream> using namespace std; int main() { int i, j, r, N, N1; N1 = 3; N = 0; r = 5; for (i = 0; i < r; i++) { if (i <= r / 2) { N = N1; for (j = 0; j <= i; j++) { N++; } N1 = N; for (j = 0; j <= i; j++) { N--; cout << N << " "; } cout << endl; } else { for (j = i; j < r; j++) { N--; cout << N << " "; } cout << endl; } } } |
Java
// Java program for incrementing // and decrementing triangle pattern class GFG { public static void main(String[] args) { int i, j, r, N, N1; N1 = 3; N = 0; r = 5; for (i = 0; i < r; i++) { if (i <= r / 2) { N = N1; for (j = 0; j <= i; j++) { N++; } N1 = N; for (j = 0; j <= i; j++) { N--; System.out.print(N + " "); } System.out.println(); } else { for (j = i; j < r; j++) { N--; System.out.print(N + " "); } System.out.println(); } } }}; // This code is contributed // by ChitraNayal |
Python 3
# python 3 program for incrementing # and decrementing triangle pattern if __name__ == "__main__": N1 = 3 N = 0; r = 5; for i in range( r): if i <= r // 2: N = N1 for j in range(i + 1): N += 1 N1 = N for j in range(i + 1): N -= 1 print(N, end = " ") print() else : for j in range(i, r): N -= 1 print(N, end = " ") print() # This code is contributed # by ChitraNayal |
C#
// C# program for incrementing // and decrementing triangle pattern using System; class GFG { public static void Main() { int i, j, r, N, N1; N1 = 3; N = 0; r = 5; for (i = 0; i < r; i++) { if (i <= r / 2) { N = N1; for (j = 0; j <= i; j++) { N++; } N1 = N; for (j = 0; j <= i; j++) { N--; Console.Write(N + " "); } Console.Write("\n"); } else { for (j = i; j < r; j++) { N--; Console.Write(N + " "); } Console.Write("\n"); } } }}; // This code is contributed // by ChitraNayal |
PHP
<?php // PHP program for incrementing // and decrementing triangle pattern $N1 = 3; $N = 0; $r = 5; for ($i = 0; $i < $r; $i++) { if ($i <= $r / 2) { $N = $N1; for ($j = 0; $j <= $i; $j++) { $N++; } $N1 = $N; for ($j = 0; $j <= $i; $j++) { $N--; echo $N ." "; } echo "\n"; } else { for ($j = $i; $j < $r; $j++) { $N--; echo $N ." "; } echo "\n"; } } // This code is contributed // by ChitraNayal ?> |
Javascript
<script> // Javascript program for incrementing // and decrementing triangle pattern let i, j, r, N, N1; N1 = 3; N = 0; r = 5; for (i = 0; i < r; i++) { if (i <= r / 2) { N = N1; for (j = 0; j <= i; j++) { N++; } N1 = N; for (j = 0; j <= i; j++) { N--; document.write(N + " "); } document.write("<br>"); } else { for (j = i; j < r; j++) { N--; document.write(N + " "); } document.write("<br>"); } } // This code is contributed by avanitrachhadiya2155 </script> |
Output
3 5 4 8 7 6 5 4 3
Time Complexity: O(r2)
Auxiliary Space: O(1)
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