Given a BCD (Binary Coded Decimal), the task is to convert this to its equivalent Binary number.
Examples:
Input: 1001000
Output: 110000
Explanation:
Integer value of the given BCD is 48(0100 -> 4, 1000 -> 8).
(48)10 = (110000)2
Input: 1001001
Output: 110000
Approach: In order to solve this problem we need to split the given BCD number into binary chunks of length 4 and convert them to integer one by one to generate the final integer representation of the given BCD. Once generated, convert the integer to its binary form.
Below is the implementation of the above approach.
C++
// C++ code to convert BCD to its// equivalent Binary#include <bits/stdc++.h>using namespace std;// Function to convert BCD to Decimalstring bcdToBinary(string s){ int l = s.length(); int num = 0; int mul = 1; int sum = 0; // If the length of given BCD is not // divisible by 4 for (int i = l % 4 - 1; i >= 0; i--) { sum += (s[i] - '0') * mul; mul *= 2; } num = sum; sum = 0; mul = pow(2, 3); int ctr = 0; for (int i = l % 4; i < l; i++) { ctr++; sum += (s[i] - '0') * mul; mul /= 2; if (ctr == 4) { num = num * 10 + sum; sum = 0; mul = pow(2, 3); ctr = 0; } } // Convert decimal to binary string ans = ""; while (num > 0) { ans += (char)(num % 2 + '0'); num /= 2; } reverse(ans.begin(), ans.end()); return ans;}// Driver Codeint main(){ string s = "1001000"; // Function Call cout << bcdToBinary(s); return 0;} |
Java
// Java code to convert BCD to its// equivalent Binaryimport java.io.*; import java.util.*; class GFG{ // Function to convert BCD to Decimalstatic String bcdToBinary(String s){ int l = s.length(); int num = 0; int mul = 1; int sum = 0; // If the length of given BCD is not // divisible by 4 for(int i = l % 4 - 1; i >= 0; i--) { sum += (s.charAt(i) - '0') * mul; mul *= 2; } num = sum; sum = 0; mul = (int)Math.pow(2, 3); int ctr = 0; for(int i = l % 4; i < l; i++) { ctr++; sum += (s.charAt(i) - '0') * mul; mul /= 2; if (ctr == 4) { num = num * 10 + sum; sum = 0; mul = (int)Math.pow(2, 3); ctr = 0; } } // Convert decimal to binary String ans = ""; while (num > 0) { ans += (char)(num % 2 + '0'); num /= 2; } StringBuilder ans1 = new StringBuilder(); // Append a string into StringBuilder input1 ans1.append(ans); // Reverse StringBuilder input1 ans = ans1.reverse().toString(); return ans;}// Driver codepublic static void main(String[] args) { String s = "1001000"; // Function call System.out.println(bcdToBinary(s));} }// This code is contributed by coder001 |
Python3
# Python3 code to convert # BCD to its equivalent Binary# Function to convert # BCD to Decimaldef bcdToBinary(s): l = len(s) num = 0; mul = 1; sum = 0; # If the length of given # BCD is not divisible by 4 for i in range(l % 4 - 1, -1, -1): sum += (ord(s[i]) - ord('0')) * mul; mul *= 2; num = sum; sum = 0; mul = pow(2, 3); ctr = 0; for i in range(l % 4, l): ctr += 1; sum += (ord(s[i]) - ord('0')) * mul; mul //= 2; if (ctr == 4): num = num * 10 + sum; sum = 0; mul = pow(2, 3); ctr = 0; # Convert decimal to binary ans = ""; while (num > 0): ans += (chr((num % 2) + ord('0'))); num //= 2; ans = ans[:: -1] return ans;# Driver codeif __name__ == "__main__": s = "1001000"; # Function Call print(bcdToBinary(s));# This code is contributed by rutvik_56 |
C#
// C# code to convert BCD to its// equivalent Binaryusing System;using System.Text;public class GFG{ // Function to convert BCD to Decimalstatic String bcdToBinary(String s){ int l = s.Length; int num = 0; int mul = 1; int sum = 0; // If the length of given BCD is not // divisible by 4 for(int i = l % 4 - 1; i >= 0; i--) { sum += (s[i] - '0') * mul; mul *= 2; } num = sum; sum = 0; mul = (int)Math.Pow(2, 3); int ctr = 0; for(int i = l % 4; i < l; i++) { ctr++; sum += (s[i] - '0') * mul; mul /= 2; if (ctr == 4) { num = num * 10 + sum; sum = 0; mul = (int)Math.Pow(2, 3); ctr = 0; } } // Convert decimal to binary String ans = ""; while (num > 0) { ans += (char)(num % 2 + '0'); num /= 2; } StringBuilder ans1 = new StringBuilder(); // Append a string into StringBuilder input1 ans1.Append(ans); // Reverse StringBuilder input1 ans = reverse(ans1.ToString()); return ans;}static String reverse(String input) { char[] a = input.ToCharArray(); int l, r = a.Length - 1; for (l = 0; l < r; l++, r--) { char temp = a[l]; a[l] = a[r]; a[r] = temp; } return String.Join("",a); } // Driver codepublic static void Main(String[] args) { String s = "1001000"; // Function call Console.WriteLine(bcdToBinary(s));} }// This code is contributed by shikhasingrajput |
Javascript
<script>// Javascript code to convert BCD to its// equivalent Binary// Function to convert BCD to Decimalfunction bcdToBinary(s){ let l = s.length; let num = 0; let mul = 1; let sum = 0; // If the length of given BCD is not // divisible by 4 for (let i = l % 4 - 1; i >= 0; i--) { sum += (s[i].charCodeAt(0) - '0'.charCodeAt(0)) * mul; mul *= 2; } num = sum; sum = 0; mul = Math.pow(2, 3); let ctr = 0; for (let i = l % 4; i < l; i++) { ctr++; sum += (s[i].charCodeAt(0) - '0'.charCodeAt(0)) * mul; mul = Math.floor(mul / 2); if (ctr == 4) { num = num * 10 + sum; sum = 0; mul = Math.pow(2, 3); ctr = 0; } } // Convert decimal to binary let ans = ""; while (num > 0) { ans += String.fromCharCode(num % 2 + '0'.charCodeAt(0)); num = Math.floor(num / 2); } ans = ans.split("").reverse().join("") console.log(ans) return ans;}// Driver Codelet s = "1001000";// Function Calldocument.write(bcdToBinary(s));// This code is contributed by _saurabh_jaiswal</script> |
Output:
110000
Time Complexity: O(N) where N denotes the length of the BCD string provided
Auxiliary Space: O(1)
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