Given an array of positive integers. Replace every element by the product of all other elements of the array.
Examples:
Input : arr[] = { 2, 3, 3, 5, 7 }
Output : 315 210 210 126 90
Approach :
- First, take the product of all the element of the array.
- Now replace each element by the product divided by that element.
- Print the modified array.
Below is the implementation of above approach:
C++
// C++ program to Replace every element// by the product of all other elements#include "iostream"using namespace std;void ReplaceElements(int arr[], int n){ int prod = 1; // Calculate the product of all the elements for (int i = 0; i < n; ++i) { prod *= arr[i]; } // Replace every element product // of all other elements for (int i = 0; i < n; ++i) { arr[i] = prod / arr[i]; }}int main(){ int arr[] = { 2, 3, 3, 5, 7 }; int n = sizeof(arr) / sizeof(arr[0]); ReplaceElements(arr, n); // Print the modified array. for (int i = 0; i < n; ++i) { cout << arr[i] << " "; } return 0;} |
Java
// Java program to Replace every element// by the product of all other elementsclass GFG{static void ReplaceElements(int arr[], int n){ int prod = 1; // Calculate the product of all the elements for (int i = 0; i < n; ++i) { prod *= arr[i]; } // Replace every element product // of all other elements for (int i = 0; i < n; ++i) { arr[i] = prod / arr[i]; }}public static void main(String[] args){ int arr[] = { 2, 3, 3, 5, 7 }; int n = arr.length; ReplaceElements(arr, n); // Print the modified array. for (int i = 0; i < n; ++i) { System.out.print(arr[i]+" "); } System.out.println("");}}// This code is contributed by mits |
Python 3
# Python 3 program to Replace every # element by the product of all # other elementsdef ReplaceElements(arr, n): prod = 1 # Calculate the product of # all the elements for i in range(n): prod *= arr[i] # Replace every element product # of all other elements for i in range(n) : arr[i] = prod // arr[i]# Driver Codeif __name__ == "__main__": arr = [ 2, 3, 3, 5, 7 ] n = len(arr) ReplaceElements(arr, n) # Print the modified array. for i in range( n): print(arr[i], end = " ")# This code is contributed# by ChitraNayal |
C#
// C# program to Replace every element // by the product of all other elements using System;class GFG{static void ReplaceElements(int []arr, int n) { int prod = 1; // Calculate the product of // all the elements for (int i = 0; i < n; ++i) { prod *= arr[i]; } // Replace every element product // of all other elements for (int i = 0; i < n; ++i) { arr[i] = prod / arr[i]; } } // Driver Codestatic public void Main (){ int []arr = { 2, 3, 3, 5, 7 }; int n = arr.Length; ReplaceElements(arr, n); // Print the modified array. for (int i = 0; i < n; ++i) { Console.Write(arr[i]+" "); } Console.WriteLine(""); } } // This code is contributed by ajit |
PHP
<?php// PHP program to Replace every element// by the product of all other elementsfunction ReplaceElements($arr, $n){ $prod = 1; // Calculate the product of all // the elements for ($i = 0; $i < $n; ++$i) { $prod *= $arr[$i]; } // Replace every element product // of all other elements for ($i = 0; $i < $n; ++$i) { $arr[$i] = (int)($prod / $arr[$i]); } return $arr;}// Driver Code$arr = array( 2, 3, 3, 5, 7 );$n = sizeof($arr);$arr1 = ReplaceElements($arr, $n);// Print the modified array.for ($i = 0; $i < $n; ++$i) { echo $arr1[$i] . " ";}// This code is contributed // by Akanksha Rai?> |
Javascript
<script> // Javascript program to Replace every element // by the product of all other elements function ReplaceElements(arr, n) { let prod = 1; // Calculate the product of // all the elements for (let i = 0; i < n; ++i) { prod *= arr[i]; } // Replace every element product // of all other elements for (let i = 0; i < n; ++i) { arr[i] = parseInt(prod / arr[i], 10); } } let arr = [ 2, 3, 3, 5, 7 ]; let n = arr.length; ReplaceElements(arr, n); // Print the modified array. for (let i = 0; i < n; ++i) { document.write(arr[i]+" "); } </script> |
Output
315 210 210 126 90
Complexity Analysis:
- Time Complexity: O(N)
- Auxiliary Space: O(1)
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