The d3.timeThursdays() function in D3.js is used to return all the dates based on Thursday in the given range of start and end date.
Syntax:
d3.timeThursdays( start, end, step );
Parameters: This function accept three parameters which are given below:
- Start: This parameter holds the given start date.
- end: This parameter holds the given end date.
- step: It is the optional parameter which holds the value used to skip dates.
Return Value: This function returns all the dates based on Thursday.
Below programs illustrate the d3.timeThursdays() function in D3.js:
Example 1:
<!DOCTYPE html> <html>   <head>     <title>         D3.js | d3.timeThursdays() Function     </title>           <script src =     </script> </head>   <body>     <script>                   // Initialising start and end date         var start = new Date(2015, 07, 01);         var end = new Date(2015, 07, 30);                   // Calling the timeThursdays() function         // without step value         var a = d3.timeThursdays(start, end);                   // Getting the Thursday dates         console.log(a);     </script> </body>   </html>                    |
Output:
["2015-08-05T18:30:00.000Z", "2015-08-12T18:30:00.000Z", "2015-08-19T18:30:00.000Z", "2015-08-26T18:30:00.000Z"]
Example 2:
<!DOCTYPE html> <html>   <head>     <title>         D3.js | d3.timeThursdays() Function     </title>           <script src =     </script> </head>   <body>     <script>                   // Initialising start and end date          var start = new Date(2015, 07, 01);          var end = new Date(2015, 07, 30);                      // Calling the timeThursdays() function          // with step value          var a = d3.timeThursdays(start, end, 2);                      // Getting the Thursday dates          console.log(a);     </script> </body>   </html>                    |
Output:
["2015-08-05T18:30:00.000Z", "2015-08-19T18:30:00.000Z"]
Reference: https://devdocs.io/d3~5/d3-time#timeThursdays
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