In Sympy, the function perpendicular_line() is used to create a new Line perpendicular to the given linear entity which passes through the given point p.
Syntax: Line.perpendicular_line(p) Parameters: p: Point Returns:line
Example #1:
Python3
# import sympy and Point, Linefrom sympy import Point, Line p1, p2, p3 = Point(0, 0), Point(2, 3), Point(-2, 2) l1 = Line(p1, p2) # using perpendicular_line() methodl2 = l1.perpendicular_line(p3) # checking l2 is perpendicular to l1 using is_perpendicular() methodisPerpendicular = l1.is_perpendicular(l2) print(isPerpendicular) |
Output:
True
Example #2:
Python3
# import sympy and Point3D, Line3Dfrom sympy import Point3D, Line3D p1, p2, p3 = Point3D(0, 0, 0), Point3D(2, 3, 4), Point3D(-2, 2, 0) l1 = Line3D(p1, p2) # using perpendicular_line() methodl2 = l1.perpendicular_line(p3) # checking l2 is perpendicular to l1 using is_perpendicular() methodisPerpendicular = l2 = l1.is_perpendicular(p3) print(isPerpendicular) |
Output:
True
… [Trackback]
[…] Here you will find 24138 more Info to that Topic: geeksforgeeks.org/python-sympy-line-perpendicular-line-method-2/ […]