Given N coins, the task is to find who win the coin game.
Coin game is a game in which each player picks coins from the given N coins in such a way that he can pick coins ranging from 1 to 5 coins in one turn and the game continues for both the players. The player who picks the last coin loses the game.
Examples:
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Input: N = 4 Output: First Player Explanation: Player 1 pick 3 coins and Player 2 pick last coin Input: N = 7 Output: Second Player
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Approach:Â
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- As the player can take coins ranging from 1 to 5 inclusively and if a player loses it means that he had only 1 coin, otherwise, he could have taken 1 less coin than available coins and force another player to lose. So now we will consider the case when the second player is going to win, which means the first player had only one coin.
- For N = 1, second player is going to win, for N = 2 to 6, first player can choose 1 less coin than N, and force the second player to lose so discard them, for N = 7, first player can choose coin 1 to 5, that’s going to leave coin ranging from 6 to 2, and then second player can choose 1 to 5, and to win second player will intelligently choose 1 less coin forcing first to lose, So basically starting from 1, all the numbers on a gap of 6(as whatever first player choose, second player will choose coins equal to difference of 6 and coins chosen by the first player) will be the winning for second player.
- Finally, we just have to check if n is of form 6*c+1 if it is then the second player going to win, otherwise, the first player going to win.
Below is the implementation for the above approach:Â
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C++
// C++ program to find the player// who wins the gameÂ
#include <bits/stdc++.h>using namespace std;Â
// Function to check the // winning playervoid findWinner(int n){    // As discussed in the     // above approach    if ((n - 1) % 6 == 0) {        cout << "Second Player wins the game";    }    else {        cout << "First Player wins the game";    }}Â
// Driver functionint main(){Â
    int n = 7;    findWinner(n);} |
Java
// Java program to find the player// who wins the gameclass GFG{Â
// Function to check the // winning playerstatic void findWinner(int n){    // As discussed in the     // above approach    if ((n - 1) % 6 == 0)    {        System.out.println("Second Player wins the game");    }    else    {        System.out.println("First Player wins the game");    }}Â
// Driver Codepublic static void main(String[] args) {Â Â Â Â int n = 7;Â Â Â Â findWinner(n);}}Â
// This code is contributed by Rajput-Ji |
Python3
# Python3 program to find the player# who wins the gameÂ
# Function to check the # winning playerdef findWinner(n):         # As discussed in the     # above approach    if ((n - 1) % 6 == 0):         print("Second Player wins the game");    else:        print("First Player wins the game");     # Driver Codeif __name__ == '__main__':    n = 7;    findWinner(n);Â
# This code is contributed by 29AjayKumar |
C#
// C# program to find the player// who wins the gameÂ
using System;Â
class GFG{         // Function to check the     // winning player    static void findWinner(int n)    {        // As discussed in the         // above approach        if ((n - 1) % 6 == 0)        {            Console.WriteLine("Second Player wins the game");        }        else        {            Console.WriteLine("First Player wins the game");        }    }         // Driver Code    public static void Main()     {        int n = 7;        findWinner(n);    }}Â
// This code is contributed by AnkitRai01 |
Javascript
<script>Â
// JavaScript program to find the player// who wins the gameÂ
// Function to check the// winning playerfunction findWinner(n){    // As discussed in the    // above approach    if ((n - 1) % 6 == 0) {        document.write("Second Player wins the game");    }    else {        document.write("First Player wins the game");    }}Â
// Driver functionvar n = 7;findWinner(n);Â
</script> |
Output:Â
Second Player wins the game
Time Complexity:
Auxiliary Space: O(1)
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