Given a dictionary with values as delimiter separated values, the task is to write a python program to convert each string as different value in list of dictionaries.
Input : test_dict = {“Gfg” : “1:2:3”, “best” : “4:8:11”}
Output : [{‘Gfg’: ‘1’, ‘best’: ‘4’}, {‘Gfg’: ‘2’, ‘best’: ‘8’}, {‘Gfg’: ‘3’, ‘best’: ’11’}]
Explanation : List after dictionary values split.
Input : test_dict = {“Gfg” : “1:2:3”}
Output : [{‘Gfg’: ‘1’}, {‘Gfg’: ‘2”}, {‘Gfg’: ‘3’}]
Explanation : List after dictionary values split.
Method : Using loop and split()
The combination of above functions can be used to solve this problem. In this, we perform splitting of values of each key’s value and render it as separate value in a list of dictionaries.
Example:
Python3
# Python3 code to demonstrate working of# Convert dictionary string values to Dictionaries List# Using loopfrom collections import defaultdict# initializing dictionarytest_dict = {"Gfg": "1:2:3:7:9", "best": "4:8", "good": "2"}# printing original dictionaryprint("The original dictionary is : " + str(test_dict))# create empty meshtemp = defaultdict(dict)for key in test_dict: # iterate for each of splitted values for idx in range(len(test_dict[key].split(':'))): try: temp[idx][key] = test_dict[key].split(':')[idx] # handle case with No value in split except Exception as e: temp[idx][key] = Noneres = []for key in temp: # converting nested dictionaries to list of dictionaries res.append(temp[key])# printing resultprint("Required dictionary list : " + str(res)) |
Output:
The original dictionary is : {‘Gfg’: ‘1:2:3:7:9’, ‘best’: ‘4:8’, ‘good’: ‘2’}
Required dictionary list : [{‘Gfg’: ‘1’, ‘best’: ‘4’, ‘good’: ‘2’}, {‘Gfg’: ‘2’, ‘best’: ‘8’}, {‘Gfg’: ‘3’}, {‘Gfg’: ‘7’}, {‘Gfg’: ‘9’}]
Time Complexity: O(n*n)
Auxiliary Space: O(n)
