The java.lang.Math.floor() returns the double value that is less than or equal to the argument and is equal to the nearest mathematical integer. Note:
- If the argument is Integer, then the result is Integer.
- If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.
public static double floor(double a) a : the argument whose floor value is to be determined Returns : This method returns the double value that is less than or equal to the argument and is equal to the nearest mathematical integer.
Example 01:To show working of java.lang.Math.floor() method.Â
java
// Java program to demonstrate working// of java.lang.Math.floor() methodÂ
import java.lang.Math;Â
class Gfg {Â
    // Main driver code    public static void main(String args[])    {        double a = 4.3;        double b = 1.0 / 0;        double c = 0.0;        double d = -0.0;        double e = -2.3;Â
        System.out.println(Math.floor(a));Â
        // Input Infinity, Output Infinity        System.out.println(Math.floor(b));Â
        // Input Positive Zero, Output Positive Zero        System.out.println(Math.floor(c));Â
        // Input Negative Zero, Output Negative Zero        System.out.println(Math.floor(d));Â
        // Input -2.3, Output -3.0        // Nearest Integer(-3.0) < less than (-2.3)        System.out.println(Math.floor(e));    }} |
Output:
4.0 Infinity 0.0 -0.0 -3.0
Example 02:To show the working of floor() with a positive double value.
Java
import java.io.*;Â
class GFG {Â Â Â Â public static void main(String[] args)Â Â Â Â {Â Â Â Â Â Â Â Â double number = 3.5; // double num-3.5Â Â Â Â Â Â Â Â double result = Math.floor(number);Â Â Â Â Â Â Â Â System.out.println(result); // Output: 3.0Â Â Â Â }} |
Output :Â
3.0
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